Consider the group homomorphism phi:M2(R)--->R,given by phi(A)=trc(A)....
Group Homomorphism from M2(R) to R
The given group homomorphism is φ : M2(R) → R defined by φ(A) = trc(A), where M2(R) denotes the set of 2x2 matrices with real entries, and trc(A) denotes the trace of the matrix A.
Definition of Group Homomorphism
A group homomorphism is a function between two groups that preserves the group operation. In this case, the groups are M2(R) and R.
Kernel of the Homomorphism
The kernel of a homomorphism is the set of elements in the domain that map to the identity element in the codomain. In this case, we need to find the set of matrices A in M2(R) such that φ(A) = 0.
Finding the Kernel
Let A = [[a, b], [c, d]] be a matrix in M2(R). Then the trace of A is trc(A) = a + d.
To find the kernel, we need to solve the equation φ(A) = trc(A) = 0.
a + d = 0
This equation implies that a = -d.
So, the kernel consists of matrices of the form A = [[a, b], [-a, d]], where a and d are real numbers.
Isomorphism and the Kernel
To determine which map the kernel is isomorphic to, we need to consider the properties of the kernel.
Kernel of φ is isomorphic to the additive group of real numbers (R, +)
The kernel of φ consists of matrices of the form A = [[a, b], [-a, d]], where a and d are real numbers. This set forms an additive group isomorphic to the group of real numbers (R, +) under addition.
Explanation
The isomorphism between the kernel of φ and the additive group of real numbers (R, +) can be established by considering the following:
1. Identity Element: The zero matrix [[0, 0], [0, 0]] is the identity element in the kernel, which corresponds to the additive identity in the group of real numbers (R, +), i.e., 0.
2. Closure: Addition of matrices in the kernel results in another matrix in the kernel, and addition of real numbers in (R, +) results in another real number.
3. Inverses: Every matrix in the kernel has an inverse within the kernel, where the additive inverse of [[a, b], [-a, d]] is [[-a, -b], [a, -d]]. Similarly, every real number in (R, +) has an additive inverse.
4. Associativity and Commutativity: Addition of matrices in the kernel and addition of real numbers in (R, +) satisfy associativity and commutativity.
Therefore, the kernel of φ is isomorphic to the additive group of real numbers (R, +).
Summary
The kernel of the group homomorphism φ : M2(R) → R, given by φ(A) = trc(A), is isomorphic to the additive group of real numbers (R, +). This is because the elements in the kernel, matrices of the form A =
Consider the group homomorphism phi:M2(R)--->R,given by phi(A)=trc(A)....
Group homomorphism phi:M2(R)--->R
The group homomorphism phi:M2(R)--->R is defined by phi(A)=trc(A), where M2(R) is the group of 2x2 matrices with real entries, R is the group of real numbers, and trc(A) denotes the trace of matrix A.
Definition of Trace
The trace of a matrix A = [a11 a12; a21 a22] is defined as the sum of its diagonal elements, i.e., trc(A) = a11 + a22.
Group Homomorphism
A group homomorphism is a map between two groups that preserves the group structure. In this case, phi is a group homomorphism from M2(R) to R because it satisfies the following properties:
1. phi(A + B) = trc(A + B) = trc(A) + trc(B) for all A, B in M2(R)
2. phi(kA) = trc(kA) = k * trc(A) for all A in M2(R) and k in R
Ker(phi)
The kernel of a group homomorphism phi is the set of elements in the domain that map to the identity element in the codomain. In this case, we need to find the matrices A in M2(R) such that phi(A) = 0.
Let's consider a matrix A = [a11 a12; a21 a22]. The trace of A is given by trc(A) = a11 + a22. For phi(A) to be 0, we have the equation a11 + a22 = 0.
Isomorphism with R2
To find the kernel of phi, we need to solve the equation a11 + a22 = 0. This equation represents a line in the plane of 2x2 matrices. The kernel of phi corresponds to the set of matrices that lie on this line.
Considering the equation a11 + a22 = 0, we can rewrite it as a11 = -a22. This means that for any value of a22, we can choose a11 = -a22 to satisfy the equation. Therefore, the kernel of phi is isomorphic to R, the set of real numbers.
We can establish an isomorphism between the kernel of phi and R by mapping each real number r to the matrix A = [-r r; 0 0]. The trace of A is trc(A) = -r + 0 = -r, which corresponds to the real number r. This mapping is a bijection and preserves the group structure, so the kernel of phi is isomorphic to R.
Summary
- The group homomorphism phi:M2(R) ---> R is defined by phi(A) = trc(A), where trc(A) denotes the trace of matrix A.
- The kernel of phi is the set of matrices A in M2(R) such that trc(A) = 0.
- The kernel of phi is isomorphic to R, the set of real numbers.
- An isomorphism can be established by mapping each real number r to the matrix A = [-r r; 0 0], which preserves the group structure and the trace.