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During the transition time or turn-on time
- a)The forward anode voltage decreases from 90 % to 10 % & the anode current also decreases from 90 to 10 % of the initial value
- b)The forward anode voltage increases from 10 % to 90 % & the anode current also increases from 10 % to 90 % of the initial value
- c)The forward anode voltage decreases from 90 % to 10 % & the anode current increases from 10 % to 90 % of the initial value
- d)The forward anode voltage increases from 10 % to 90 % & the anode current decreases from 90% to 10% of the initial value
Correct answer is option 'C'. Can you explain this answer?
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During the transition time or turn-on timea)The forward anode voltage ...
The correct answer is C: The forward anode voltage decreases from 90% to 10% and the anode current increases from 10% to 90% of the initial value during the transition time or turn-on time.
During the transition or turn-on time of a device like a diode or transistor, the device undergoes a change in its conduction state from off (blocking state) to on (conducting state). For a diode, this refers to the process of transitioning from reverse-biased to forward-biased conduction.
In the case of a diode, during the turn-on time, the forward anode voltage gradually decreases from 90% to 10% of the initial value. This means that the voltage across the diode decreases, allowing it to start conducting current.
Simultaneously, the anode current increases from 10% to 90% of the initial value. As the forward voltage decreases, the diode starts conducting and allows more current to flow through it.
Therefore, during the transition time or turn-on time, the forward anode voltage decreases from 90% to 10%, and the anode current increases from 10% to 90% of the initial value. The correct answer is C.
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During the transition time or turn-on timea)The forward anode voltage ...
Explanation:
- Transition time or turn-on time: This refers to the time taken by a device to switch from its off state to its on state.
- During the transition time:
- The forward anode voltage decreases from 90% to 10% of the initial value. This is because during turn-on, the voltage across the anode decreases as the device transitions from off to on state.
- The anode current increases from 10% to 90% of the initial value. This is because as the device turns on, the current flowing through it increases from a low value to a higher value.
- Conclusion:
- Therefore, during the transition time or turn-on time, the forward anode voltage decreases from 90% to 10% of the initial value, while the anode current increases from 10% to 90% of the initial value. This behavior is consistent with the operation of the device during turn-on.
- Transition time or turn-on time: This refers to the time taken by a device to switch from its off state to its on state.
- During the transition time:
- The forward anode voltage decreases from 90% to 10% of the initial value. This is because during turn-on, the voltage across the anode decreases as the device transitions from off to on state.
- The anode current increases from 10% to 90% of the initial value. This is because as the device turns on, the current flowing through it increases from a low value to a higher value.
- Conclusion:
- Therefore, during the transition time or turn-on time, the forward anode voltage decreases from 90% to 10% of the initial value, while the anode current increases from 10% to 90% of the initial value. This behavior is consistent with the operation of the device during turn-on.
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During the transition time or turn-on timea)The forward anode voltage decreases from 90 % to 10 % & the anode current also decreases from 90 to 10 % of the initial valueb)The forward anode voltage increases from 10 % to 90 % & the anode current also increases from 10 % to 90 % of the initial valuec)The forward anode voltage decreases from 90 % to 10 % & the anode current increases from 10 % to 90 % of the initial valued)The forward anode voltage increases from 10 % to 90 % & the anode current decreases from 90% to 10% of the initial valueCorrect answer is option 'C'. Can you explain this answer?
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