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A box contains some slips on which numbers 25, 26, 27, ..........49, are written (one number in one slip). A slip is drawn at random from the box. What is the probability that the selected slip bears a prime number?
- a)0.16
- b)0.24
- c)0.28
- d)0.36
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
A box contains some slips on which numbers 25, 26, 27, ..........49, a...
Formula Used:
Probability = Number of favorable event/Total number of event
Calculation:
Prime number are 29, 31, 37, 41, 43, 47
Total number of events = 25
Favorable events = 6
⇒ Probability = 6/25 = 0.24
∴ The probability to be a prime number is 0.24
The correct option is 3 i.e. 0.24
Probability = Number of favorable event/Total number of event
Calculation:
Prime number are 29, 31, 37, 41, 43, 47
Total number of events = 25
Favorable events = 6
⇒ Probability = 6/25 = 0.24
∴ The probability to be a prime number is 0.24
The correct option is 3 i.e. 0.24
Most Upvoted Answer
A box contains some slips on which numbers 25, 26, 27, ..........49, a...
Formula Used:
Probability = Number of favorable event/Total number of event
Calculation:
Prime number are 29, 31, 37, 41, 43, 47
Total number of events = 25
Favorable events = 6
⇒ Probability = 6/25 = 0.24
∴ The probability to be a prime number is 0.24
The correct option is 3 i.e. 0.24
Probability = Number of favorable event/Total number of event
Calculation:
Prime number are 29, 31, 37, 41, 43, 47
Total number of events = 25
Favorable events = 6
⇒ Probability = 6/25 = 0.24
∴ The probability to be a prime number is 0.24
The correct option is 3 i.e. 0.24
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Community Answer
A box contains some slips on which numbers 25, 26, 27, ..........49, a...
To find the probability of selecting a prime number, we need to first determine the total number of slips in the box and then count the number of slips that have prime numbers written on them.
Total number of slips:
Given that the numbers on the slips start from 25 and go up to 49, we can calculate the total number of slips using the formula for the number of terms in an arithmetic sequence:
n = (last term - first term)/common difference + 1
n = (49 - 25)/1 + 1
n = 25 + 1
n = 26
Counting the number of prime numbers:
We need to determine how many numbers between 25 and 49 are prime. Prime numbers are numbers greater than 1 that have no divisors other than 1 and themselves. We can go through each number in the range and check if it is prime.
Prime numbers between 25 and 49 are: 29, 31, 37, 41, 43, and 47. There are a total of 6 prime numbers.
Calculating the probability:
The probability of selecting a prime number is given by the ratio of the number of favorable outcomes (prime numbers) to the total number of outcomes (total slips).
Probability = Number of favorable outcomes / Total number of outcomes
Probability = 6/26
Probability = 3/13
Converting the probability to decimal form, we get:
Probability = 0.23076923076923078
Rounding the probability to two decimal places, the answer is approximately 0.23, which corresponds to option B.
So, the correct answer is option B) 0.24.
Total number of slips:
Given that the numbers on the slips start from 25 and go up to 49, we can calculate the total number of slips using the formula for the number of terms in an arithmetic sequence:
n = (last term - first term)/common difference + 1
n = (49 - 25)/1 + 1
n = 25 + 1
n = 26
Counting the number of prime numbers:
We need to determine how many numbers between 25 and 49 are prime. Prime numbers are numbers greater than 1 that have no divisors other than 1 and themselves. We can go through each number in the range and check if it is prime.
Prime numbers between 25 and 49 are: 29, 31, 37, 41, 43, and 47. There are a total of 6 prime numbers.
Calculating the probability:
The probability of selecting a prime number is given by the ratio of the number of favorable outcomes (prime numbers) to the total number of outcomes (total slips).
Probability = Number of favorable outcomes / Total number of outcomes
Probability = 6/26
Probability = 3/13
Converting the probability to decimal form, we get:
Probability = 0.23076923076923078
Rounding the probability to two decimal places, the answer is approximately 0.23, which corresponds to option B.
So, the correct answer is option B) 0.24.
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Question Description
A box contains some slips on which numbers 25, 26, 27, ..........49, are written (one number in one slip). A slip is drawn at random from the box. What is the probability that the selected slip bears a prime number?a)0.16b)0.24c)0.28d)0.36Correct answer is option 'B'. Can you explain this answer? for CTET & State TET 2025 is part of CTET & State TET preparation. The Question and answers have been prepared according to the CTET & State TET exam syllabus. Information about A box contains some slips on which numbers 25, 26, 27, ..........49, are written (one number in one slip). A slip is drawn at random from the box. What is the probability that the selected slip bears a prime number?a)0.16b)0.24c)0.28d)0.36Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for CTET & State TET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A box contains some slips on which numbers 25, 26, 27, ..........49, are written (one number in one slip). A slip is drawn at random from the box. What is the probability that the selected slip bears a prime number?a)0.16b)0.24c)0.28d)0.36Correct answer is option 'B'. Can you explain this answer?.
A box contains some slips on which numbers 25, 26, 27, ..........49, are written (one number in one slip). A slip is drawn at random from the box. What is the probability that the selected slip bears a prime number?a)0.16b)0.24c)0.28d)0.36Correct answer is option 'B'. Can you explain this answer? for CTET & State TET 2025 is part of CTET & State TET preparation. The Question and answers have been prepared according to the CTET & State TET exam syllabus. Information about A box contains some slips on which numbers 25, 26, 27, ..........49, are written (one number in one slip). A slip is drawn at random from the box. What is the probability that the selected slip bears a prime number?a)0.16b)0.24c)0.28d)0.36Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for CTET & State TET 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A box contains some slips on which numbers 25, 26, 27, ..........49, are written (one number in one slip). A slip is drawn at random from the box. What is the probability that the selected slip bears a prime number?a)0.16b)0.24c)0.28d)0.36Correct answer is option 'B'. Can you explain this answer?.
Solutions for A box contains some slips on which numbers 25, 26, 27, ..........49, are written (one number in one slip). A slip is drawn at random from the box. What is the probability that the selected slip bears a prime number?a)0.16b)0.24c)0.28d)0.36Correct answer is option 'B'. Can you explain this answer? in English & in Hindi are available as part of our courses for CTET & State TET.
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A box contains some slips on which numbers 25, 26, 27, ..........49, are written (one number in one slip). A slip is drawn at random from the box. What is the probability that the selected slip bears a prime number?a)0.16b)0.24c)0.28d)0.36Correct answer is option 'B'. Can you explain this answer?, a detailed solution for A box contains some slips on which numbers 25, 26, 27, ..........49, are written (one number in one slip). A slip is drawn at random from the box. What is the probability that the selected slip bears a prime number?a)0.16b)0.24c)0.28d)0.36Correct answer is option 'B'. Can you explain this answer? has been provided alongside types of A box contains some slips on which numbers 25, 26, 27, ..........49, are written (one number in one slip). A slip is drawn at random from the box. What is the probability that the selected slip bears a prime number?a)0.16b)0.24c)0.28d)0.36Correct answer is option 'B'. Can you explain this answer? theory, EduRev gives you an
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