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A modulating signal is amplified by a 80% efficiency amplifier before being combined with a 20 kW carrier to generate an AM signal. The required DC input power to the amplifier, for the system to operate at 100% modulation, would be
  • a)
    5 kW
  • b)
    8.46 kW
  • c)
    12.5 kW
  • d)
    6.25 kW
Correct answer is option 'C'. Can you explain this answer?
Most Upvoted Answer
A modulating signal is amplified by a 80% efficiency amplifier before ...
Pi = Pt -Pc = 30 – 20 = 10 kW. DC input = 10/0.8 or 12.5 kW.
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Community Answer
A modulating signal is amplified by a 80% efficiency amplifier before ...

Calculating Required DC Input Power:

To calculate the required DC input power for the amplifier to operate at 100% modulation, we need to consider the efficiency of the amplifier and the power of the modulating signal.

Given Data:
- Efficiency of the amplifier = 80%
- Power of the carrier signal = 20 kW

Calculating Power of Modulating Signal:
Since the amplifier operates at 80% efficiency, the power of the modulating signal can be calculated as follows:
Modulating Power = Carrier Power / Efficiency
Modulating Power = 20 kW / 0.80
Modulating Power = 25 kW

Calculating Total Power for 100% Modulation:
For 100% modulation, the total power required would be the sum of the carrier power and modulating signal power:
Total Power = Carrier Power + Modulating Power
Total Power = 20 kW + 25 kW
Total Power = 45 kW

Therefore, the required DC input power to the amplifier for the system to operate at 100% modulation would be 45 kW.

Answer:
c) 12.5 kW
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A modulating signal is amplified by a 80% efficiency amplifier before being combined with a 20 kW carrier to generate an AM signal. The required DC input power to the amplifier, for the system to operate at 100% modulation, would bea)5 kWb)8.46 kWc)12.5 kWd)6.25 kWCorrect answer is option 'C'. Can you explain this answer?
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