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A modulating signal is amplified by a 80% efficiency amplifier before being combined with a 20 kW carrier to generate an AM signal. The required DC input power to the amplifier, for the system to operate at 100% modulation, would be
- a)5 kW
- b)8.46 kW
- c)12.5 kW
- d)6.25 kW
Correct answer is option 'C'. Can you explain this answer?
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A modulating signal is amplified by a 80% efficiency amplifier before ...
Pi = Pt -Pc = 30 – 20 = 10 kW. DC input = 10/0.8 or 12.5 kW.
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A modulating signal is amplified by a 80% efficiency amplifier before ...
To determine the required DC input power to the amplifier for the system to operate at 100% modulation, we can use the following steps:
1. Determine the power of the modulating signal:
The modulating signal is amplified by an 80% efficiency amplifier. Since the amplifier has an efficiency of 80%, it means that 80% of the input power is converted into output power. Therefore, we can calculate the power of the modulating signal as follows:
Power of modulating signal = (100% / 80%) × Power of modulating signal
Power of modulating signal = (1 / 0.8) × Power of modulating signal
Power of modulating signal = 1.25 × Power of modulating signal
2. Determine the power of the carrier signal:
The carrier signal has a power of 20 kW.
3. Determine the total power of the AM signal:
The total power of the AM signal is the sum of the power of the modulating signal and the power of the carrier signal. Therefore, we can calculate the total power of the AM signal as follows:
Total power of AM signal = Power of modulating signal + Power of carrier signal
Total power of AM signal = 1.25 × Power of modulating signal + 20 kW
4. Determine the required DC input power to the amplifier:
The DC input power to the amplifier is the total power of the AM signal divided by the efficiency of the amplifier. Therefore, we can calculate the required DC input power as follows:
Required DC input power = Total power of AM signal / Efficiency of amplifier
Required DC input power = (1.25 × Power of modulating signal + 20 kW) / 80%
5. Substitute the value of the power of the modulating signal:
Since we want the system to operate at 100% modulation, the power of the modulating signal is equal to the power of the carrier signal. Therefore, we can substitute the value of the power of the carrier signal into the equation:
Required DC input power = (1.25 × 20 kW + 20 kW) / 80%
Required DC input power = (25 kW + 20 kW) / 80%
Required DC input power = 45 kW / 80%
Required DC input power = 0.5625 × 45 kW
Required DC input power = 25.31 kW
Therefore, the required DC input power to the amplifier, for the system to operate at 100% modulation, is approximately 25.31 kW.
1. Determine the power of the modulating signal:
The modulating signal is amplified by an 80% efficiency amplifier. Since the amplifier has an efficiency of 80%, it means that 80% of the input power is converted into output power. Therefore, we can calculate the power of the modulating signal as follows:
Power of modulating signal = (100% / 80%) × Power of modulating signal
Power of modulating signal = (1 / 0.8) × Power of modulating signal
Power of modulating signal = 1.25 × Power of modulating signal
2. Determine the power of the carrier signal:
The carrier signal has a power of 20 kW.
3. Determine the total power of the AM signal:
The total power of the AM signal is the sum of the power of the modulating signal and the power of the carrier signal. Therefore, we can calculate the total power of the AM signal as follows:
Total power of AM signal = Power of modulating signal + Power of carrier signal
Total power of AM signal = 1.25 × Power of modulating signal + 20 kW
4. Determine the required DC input power to the amplifier:
The DC input power to the amplifier is the total power of the AM signal divided by the efficiency of the amplifier. Therefore, we can calculate the required DC input power as follows:
Required DC input power = Total power of AM signal / Efficiency of amplifier
Required DC input power = (1.25 × Power of modulating signal + 20 kW) / 80%
5. Substitute the value of the power of the modulating signal:
Since we want the system to operate at 100% modulation, the power of the modulating signal is equal to the power of the carrier signal. Therefore, we can substitute the value of the power of the carrier signal into the equation:
Required DC input power = (1.25 × 20 kW + 20 kW) / 80%
Required DC input power = (25 kW + 20 kW) / 80%
Required DC input power = 45 kW / 80%
Required DC input power = 0.5625 × 45 kW
Required DC input power = 25.31 kW
Therefore, the required DC input power to the amplifier, for the system to operate at 100% modulation, is approximately 25.31 kW.
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A modulating signal is amplified by a 80% efficiency amplifier before being combined with a 20 kW carrier to generate an AM signal. The required DC input power to the amplifier, for the system to operate at 100% modulation, would bea)5 kWb)8.46 kWc)12.5 kWd)6.25 kWCorrect answer is option 'C'. Can you explain this answer?
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