Electrical Engineering (EE) Exam > Electrical Engineering (EE) Questions > A 250 V DC shunt generator delivers a load c...
Start Learning for Free
A 250 V DC shunt generator delivers a load current of 195 A. The armature and shunt field resistances are 0.05 Ω and 50 Ω, respectively. What is the value of generated e.m.f. (in volts) in the armature? (Answer up to the nearest integer)
Correct answer is '260'. Can you explain this answer?
| FREE This question is part of | Download PDF Attempt this Test |
Most Upvoted Answer
A 250 V DC shunt generator delivers a load current of 195 A. The arma...
Solution:
Given:
Voltage of the generator (V) = 250 V
Load current (I) = 195 A
Armature resistance (Ra) = 0.05 Ω
Shunt field resistance (Rf) = 50 Ω
To find:
Generated electromotive force (Ea) in the armature
Using Ohm's law, we can find the voltage drop across the armature resistance and the shunt field resistance.
1. Voltage drop across the armature resistance:
Voltage drop (Va) = I * Ra
Substituting the given values:
Va = 195 A * 0.05 Ω
Va = 9.75 V
2. Voltage drop across the shunt field resistance:
Voltage drop (Vf) = I * Rf
Substituting the given values:
Vf = 195 A * 50 Ω
Vf = 9750 V
The total generated electromotive force (Eg) can be calculated by adding the voltage drops across the armature and shunt field resistances.
3. Total generated electromotive force:
Eg = V + Va + Vf
Substituting the given values:
Eg = 250 V + 9.75 V + 9750 V
Eg = 10,009.75 V
However, the question asks for the value of the generated electromotive force in the armature (Ea), so we need to subtract the voltage drop across the shunt field resistance from the total generated electromotive force.
4. Generated electromotive force in the armature:
Ea = Eg - Vf
Substituting the given values:
Ea = 10,009.75 V - 9750 V
Ea = 259.75 V
Rounding off to the nearest integer, the value of the generated electromotive force in the armature is 260 V, which matches the given correct answer.
Given:
Voltage of the generator (V) = 250 V
Load current (I) = 195 A
Armature resistance (Ra) = 0.05 Ω
Shunt field resistance (Rf) = 50 Ω
To find:
Generated electromotive force (Ea) in the armature
Using Ohm's law, we can find the voltage drop across the armature resistance and the shunt field resistance.
1. Voltage drop across the armature resistance:
Voltage drop (Va) = I * Ra
Substituting the given values:
Va = 195 A * 0.05 Ω
Va = 9.75 V
2. Voltage drop across the shunt field resistance:
Voltage drop (Vf) = I * Rf
Substituting the given values:
Vf = 195 A * 50 Ω
Vf = 9750 V
The total generated electromotive force (Eg) can be calculated by adding the voltage drops across the armature and shunt field resistances.
3. Total generated electromotive force:
Eg = V + Va + Vf
Substituting the given values:
Eg = 250 V + 9.75 V + 9750 V
Eg = 10,009.75 V
However, the question asks for the value of the generated electromotive force in the armature (Ea), so we need to subtract the voltage drop across the shunt field resistance from the total generated electromotive force.
4. Generated electromotive force in the armature:
Ea = Eg - Vf
Substituting the given values:
Ea = 10,009.75 V - 9750 V
Ea = 259.75 V
Rounding off to the nearest integer, the value of the generated electromotive force in the armature is 260 V, which matches the given correct answer.
Attention Electrical Engineering (EE) Students!
To make sure you are not studying endlessly, EduRev has designed Electrical Engineering (EE) study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in Electrical Engineering (EE).
|
Explore Courses for Electrical Engineering (EE) exam
|
|
Similar Electrical Engineering (EE) Doubts
Top Courses for Electrical Engineering (EE)View all
A 250 V DC shunt generator delivers a load current of 195 A. The armature and shunt field resistances are 0.05 Ω and 50 Ω, respectively. What is the value of generated e.m.f. (in volts) in the armature? (Answer up to the nearest integer)Correct answer is '260'. Can you explain this answer?
Question Description
A 250 V DC shunt generator delivers a load current of 195 A. The armature and shunt field resistances are 0.05 Ω and 50 Ω, respectively. What is the value of generated e.m.f. (in volts) in the armature? (Answer up to the nearest integer)Correct answer is '260'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A 250 V DC shunt generator delivers a load current of 195 A. The armature and shunt field resistances are 0.05 Ω and 50 Ω, respectively. What is the value of generated e.m.f. (in volts) in the armature? (Answer up to the nearest integer)Correct answer is '260'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 250 V DC shunt generator delivers a load current of 195 A. The armature and shunt field resistances are 0.05 Ω and 50 Ω, respectively. What is the value of generated e.m.f. (in volts) in the armature? (Answer up to the nearest integer)Correct answer is '260'. Can you explain this answer?.
A 250 V DC shunt generator delivers a load current of 195 A. The armature and shunt field resistances are 0.05 Ω and 50 Ω, respectively. What is the value of generated e.m.f. (in volts) in the armature? (Answer up to the nearest integer)Correct answer is '260'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A 250 V DC shunt generator delivers a load current of 195 A. The armature and shunt field resistances are 0.05 Ω and 50 Ω, respectively. What is the value of generated e.m.f. (in volts) in the armature? (Answer up to the nearest integer)Correct answer is '260'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 250 V DC shunt generator delivers a load current of 195 A. The armature and shunt field resistances are 0.05 Ω and 50 Ω, respectively. What is the value of generated e.m.f. (in volts) in the armature? (Answer up to the nearest integer)Correct answer is '260'. Can you explain this answer?.
Solutions for A 250 V DC shunt generator delivers a load current of 195 A. The armature and shunt field resistances are 0.05 Ω and 50 Ω, respectively. What is the value of generated e.m.f. (in volts) in the armature? (Answer up to the nearest integer)Correct answer is '260'. Can you explain this answer? in English & in Hindi are available as part of our courses for Electrical Engineering (EE).
Download more important topics, notes, lectures and mock test series for Electrical Engineering (EE) Exam by signing up for free.
Here you can find the meaning of A 250 V DC shunt generator delivers a load current of 195 A. The armature and shunt field resistances are 0.05 Ω and 50 Ω, respectively. What is the value of generated e.m.f. (in volts) in the armature? (Answer up to the nearest integer)Correct answer is '260'. Can you explain this answer? defined & explained in the simplest way possible. Besides giving the explanation of
A 250 V DC shunt generator delivers a load current of 195 A. The armature and shunt field resistances are 0.05 Ω and 50 Ω, respectively. What is the value of generated e.m.f. (in volts) in the armature? (Answer up to the nearest integer)Correct answer is '260'. Can you explain this answer?, a detailed solution for A 250 V DC shunt generator delivers a load current of 195 A. The armature and shunt field resistances are 0.05 Ω and 50 Ω, respectively. What is the value of generated e.m.f. (in volts) in the armature? (Answer up to the nearest integer)Correct answer is '260'. Can you explain this answer? has been provided alongside types of A 250 V DC shunt generator delivers a load current of 195 A. The armature and shunt field resistances are 0.05 Ω and 50 Ω, respectively. What is the value of generated e.m.f. (in volts) in the armature? (Answer up to the nearest integer)Correct answer is '260'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice A 250 V DC shunt generator delivers a load current of 195 A. The armature and shunt field resistances are 0.05 Ω and 50 Ω, respectively. What is the value of generated e.m.f. (in volts) in the armature? (Answer up to the nearest integer)Correct answer is '260'. Can you explain this answer? tests, examples and also practice Electrical Engineering (EE) tests.
|
|
Explore Courses for Electrical Engineering (EE) exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup