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A dc shunt generator delivers 195 A at a terminal voltage of 200 V. The armature resistance is 0.03Ω and field winding resistance is 40Ω. The stray losses are 900 W.The efficiency of the generator (in percentage) is equal to (Answer up to two decimal places)Correct answer is '92.64'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A dc shunt generator delivers 195 A at a terminal voltage of 200 V. The armature resistance is 0.03Ω and field winding resistance is 40Ω. The stray losses are 900 W.The efficiency of the generator (in percentage) is equal to (Answer up to two decimal places)Correct answer is '92.64'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A dc shunt generator delivers 195 A at a terminal voltage of 200 V. The armature resistance is 0.03Ω and field winding resistance is 40Ω. The stray losses are 900 W.The efficiency of the generator (in percentage) is equal to (Answer up to two decimal places)Correct answer is '92.64'. Can you explain this answer?.

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