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A generator rated 100 MVA, 12-6 kV has X, = X2 = 20% and X = 10%. Its neutral is grounded through reactance of 0 152. The generator is (b) a operating at rated voltage, load is disconnected from the system when double-line fault occurs at its terminals. Determine the sub-transient current in the faulted phases and line-to-line fault current.?
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A generator rated 100 MVA, 12-6 kV has X, = X2 = 20% and X = 10%. Its...
Generator Specifications:
- Rated Power: 100 MVA
- Voltage Rating: 12-6 kV
- Reactance: X = X2 = 20%
- Grounding Reactance: 0.152
Fault Condition:
- Load disconnected from the system
- Double-line fault occurs at the generator terminals
Determining Sub-Transient Current:
To determine the sub-transient current in the faulted phases, we need to calculate the total fault current first. The fault current is given by the formula:
IF = E / (X + Xg)
Where:
- E is the generator voltage
- X is the generator reactance
- Xg is the grounding reactance
Calculating Fault Current:
Given that the generator is operating at its rated voltage, we can substitute the values into the formula:
IF = (12 kV) / (0.2 + 0.152)
IF = 12 kV / 0.352
IF = 34.09 kA
Calculating Sub-Transient Current:
The sub-transient current is given by the formula:
Ist = IF / X2
Substituting the values:
Ist = 34.09 kA / 0.2
Ist = 170.45 kA
Determining Line-to-Line Fault Current:
The line-to-line fault current can be calculated by multiplying the sub-transient current by a factor of √3. Therefore:
Line-to-Line Fault Current = Ist * √3
Line-to-Line Fault Current = 170.45 kA * √3
Line-to-Line Fault Current = 294.77 kA
Explanation:
- The fault condition described in the question is a double-line fault, which means that two phases are short-circuited together.
- The fault current is calculated using the formula IF = E / (X + Xg), where E is the generator voltage, X is the generator reactance, and Xg is the grounding reactance.
- The sub-transient current is then calculated using the formula Ist = IF / X2, where X2 is the sub-transient reactance.
- Finally, the line-to-line fault current is determined by multiplying the sub-transient current by a factor of √3.
- The calculated values for the sub-transient current and line-to-line fault current are 170.45 kA and 294.77 kA, respectively.
- Rated Power: 100 MVA
- Voltage Rating: 12-6 kV
- Reactance: X = X2 = 20%
- Grounding Reactance: 0.152
Fault Condition:
- Load disconnected from the system
- Double-line fault occurs at the generator terminals
Determining Sub-Transient Current:
To determine the sub-transient current in the faulted phases, we need to calculate the total fault current first. The fault current is given by the formula:
IF = E / (X + Xg)
Where:
- E is the generator voltage
- X is the generator reactance
- Xg is the grounding reactance
Calculating Fault Current:
Given that the generator is operating at its rated voltage, we can substitute the values into the formula:
IF = (12 kV) / (0.2 + 0.152)
IF = 12 kV / 0.352
IF = 34.09 kA
Calculating Sub-Transient Current:
The sub-transient current is given by the formula:
Ist = IF / X2
Substituting the values:
Ist = 34.09 kA / 0.2
Ist = 170.45 kA
Determining Line-to-Line Fault Current:
The line-to-line fault current can be calculated by multiplying the sub-transient current by a factor of √3. Therefore:
Line-to-Line Fault Current = Ist * √3
Line-to-Line Fault Current = 170.45 kA * √3
Line-to-Line Fault Current = 294.77 kA
Explanation:
- The fault condition described in the question is a double-line fault, which means that two phases are short-circuited together.
- The fault current is calculated using the formula IF = E / (X + Xg), where E is the generator voltage, X is the generator reactance, and Xg is the grounding reactance.
- The sub-transient current is then calculated using the formula Ist = IF / X2, where X2 is the sub-transient reactance.
- Finally, the line-to-line fault current is determined by multiplying the sub-transient current by a factor of √3.
- The calculated values for the sub-transient current and line-to-line fault current are 170.45 kA and 294.77 kA, respectively.
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A generator rated 100 MVA, 12-6 kV has X, = X2 = 20% and X = 10%. Its neutral is grounded through reactance of 0 152. The generator is (b) a operating at rated voltage, load is disconnected from the system when double-line fault occurs at its terminals. Determine the sub-transient current in the faulted phases and line-to-line fault current.?
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A generator rated 100 MVA, 12-6 kV has X, = X2 = 20% and X = 10%. Its neutral is grounded through reactance of 0 152. The generator is (b) a operating at rated voltage, load is disconnected from the system when double-line fault occurs at its terminals. Determine the sub-transient current in the faulted phases and line-to-line fault current.? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about A generator rated 100 MVA, 12-6 kV has X, = X2 = 20% and X = 10%. Its neutral is grounded through reactance of 0 152. The generator is (b) a operating at rated voltage, load is disconnected from the system when double-line fault occurs at its terminals. Determine the sub-transient current in the faulted phases and line-to-line fault current.? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A generator rated 100 MVA, 12-6 kV has X, = X2 = 20% and X = 10%. Its neutral is grounded through reactance of 0 152. The generator is (b) a operating at rated voltage, load is disconnected from the system when double-line fault occurs at its terminals. Determine the sub-transient current in the faulted phases and line-to-line fault current.?.
A generator rated 100 MVA, 12-6 kV has X, = X2 = 20% and X = 10%. Its neutral is grounded through reactance of 0 152. The generator is (b) a operating at rated voltage, load is disconnected from the system when double-line fault occurs at its terminals. Determine the sub-transient current in the faulted phases and line-to-line fault current.? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about A generator rated 100 MVA, 12-6 kV has X, = X2 = 20% and X = 10%. Its neutral is grounded through reactance of 0 152. The generator is (b) a operating at rated voltage, load is disconnected from the system when double-line fault occurs at its terminals. Determine the sub-transient current in the faulted phases and line-to-line fault current.? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A generator rated 100 MVA, 12-6 kV has X, = X2 = 20% and X = 10%. Its neutral is grounded through reactance of 0 152. The generator is (b) a operating at rated voltage, load is disconnected from the system when double-line fault occurs at its terminals. Determine the sub-transient current in the faulted phases and line-to-line fault current.?.
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