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Two pipes A and B can fill a cistern in 37(1/2) minutes and 45 minutes respectively. Both pipes are opened. The cistern will be filled in just half an hour, if the B is turned off after:
  • a)
    5 minutes 
  • b)
    9 minutes 
  • c)
    10 minutes 
  • d)
    15 minutes 
  • e)
    12 minutes 
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
Two pipes A and B can fill a cistern in37(1/2) minutes and 45 minutes ...
Given Information:
- Pipe A can fill the cistern in 37(1/2) minutes.
- Pipe B can fill the cistern in 45 minutes.
- Both pipes are opened.

To Find:
- The time at which Pipe B needs to be turned off in order to fill the cistern in half an hour (30 minutes).

Solution:
Let's first find the filling rates of both pipes A and B.

Filling Rate of Pipe A:
Pipe A can fill the cistern in 37(1/2) minutes, which is equivalent to 75/2 minutes.
Therefore, the filling rate of Pipe A is 1/(75/2) = 2/75 cisterns per minute.

Filling Rate of Pipe B:
Pipe B can fill the cistern in 45 minutes.
Therefore, the filling rate of Pipe B is 1/45 cisterns per minute.

Combined Filling Rate:
When both pipes A and B are opened, their combined filling rate is the sum of their individual filling rates.
Combined filling rate = (2/75) + (1/45) = (6 + 5)/(225) = 11/225 cisterns per minute.

Now, let's calculate the time it would take to fill the cistern in half an hour (30 minutes) using the combined filling rate.

Time to Fill the Cistern:
Time = Volume / Rate
The volume of the cistern is 1 cistern (as it needs to be completely filled).
Rate = 11/225 cisterns per minute.
Time = 1 / (11/225) = 225/11 minutes.

We need to find the time at which Pipe B needs to be turned off to fill the cistern in exactly 30 minutes. Let's represent this time as 'x' minutes.

Therefore, the time taken by Pipe A to fill the cistern is (30 - x) minutes (as Pipe B is turned off after 'x' minutes).
Using the filling rate of Pipe A, we can write the equation:
(2/75) * (30 - x) = 1
Simplifying the equation, we get:
60 - 2x = 75
-2x = 75 - 60
-2x = 15
x = 15/2 = 7.5 minutes.

Conclusion:
Pipe B needs to be turned off after 7.5 minutes (option B) in order to fill the cistern in exactly 30 minutes.
Free Test
Community Answer
Two pipes A and B can fill a cistern in37(1/2) minutes and 45 minutes ...
Given,
Time taken by pipe A to fill the cistern = 37(1/2) minutes
Time taken by pipe B to fill the cistern = 45 minutes
Let B be turned off after x minutes.
Then, Part filled by (A+B) in x minutes + Part filled by A in (30−x)minutes = 1
Therefore,

⇒ x = 9
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Two pipes A and B can fill a cistern in37(1/2) minutes and 45 minutes respectively. Both pipes are opened. The cistern will be filled in just half an hour, if the B is turned off after:a)5 minutesb)9 minutesc)10 minutesd)15 minutese)12 minutesCorrect answer is option 'B'. Can you explain this answer?
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