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A 500 kVA transformer has constant loss of 500 W and copper losses at full load are 2,000 W.Then at what load, is the efficiency maximum ?
- a)250 kVA
- b)500 kVA
- c)1000 kVA
- d)125 kVA
Correct answer is option 'A'. Can you explain this answer?
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Most Upvoted Answer
A 500 kVA transformer has constant loss of 500 W and copper losses at ...
Calculation of Efficiency:
The efficiency of a transformer is given by the formula:
Efficiency = (Output Power / Input Power) * 100
Where,
Output Power = Copper losses + Iron losses
Input Power = Output Power + Copper losses + Iron losses
Given that the constant losses of the transformer are 500 W and copper losses at full load are 2000 W, we can calculate the input power and output power as follows:
Copper losses = 2000 W
Constant losses = 500 W
Output Power = Copper losses + Constant losses
Output Power = 2000 W + 500 W
Output Power = 2500 W
Input Power = Output Power + Copper losses + Constant losses
Input Power = 2500 W + 2000 W + 500 W
Input Power = 5000 W
Efficiency = (Output Power / Input Power) * 100
Efficiency = (2500 W / 5000 W) * 100
Efficiency = 50%
Determining the Load for Maximum Efficiency:
To determine the load at which the efficiency is maximum, we need to calculate the efficiency at different loads and compare them.
Let's assume the load on the transformer is x kVA.
Output Power = Copper losses + Constant losses
Output Power = 2000 W + 500 W
Output Power = 2500 W
Input Power = Output Power + Copper losses + Constant losses
Input Power = 2500 W + 2000 W + 500 W
Input Power = 5000 W
Efficiency = (Output Power / Input Power) * 100
Efficiency = (2500 W / 5000 W) * 100
Efficiency = 50%
We can observe that the efficiency remains constant at 50% for any load on the transformer. Therefore, the efficiency is maximum at any load.
Conclusion:
The maximum efficiency of the transformer is achieved at any load. The correct answer is option 'A' - 250 kVA.
The efficiency of a transformer is given by the formula:
Efficiency = (Output Power / Input Power) * 100
Where,
Output Power = Copper losses + Iron losses
Input Power = Output Power + Copper losses + Iron losses
Given that the constant losses of the transformer are 500 W and copper losses at full load are 2000 W, we can calculate the input power and output power as follows:
Copper losses = 2000 W
Constant losses = 500 W
Output Power = Copper losses + Constant losses
Output Power = 2000 W + 500 W
Output Power = 2500 W
Input Power = Output Power + Copper losses + Constant losses
Input Power = 2500 W + 2000 W + 500 W
Input Power = 5000 W
Efficiency = (Output Power / Input Power) * 100
Efficiency = (2500 W / 5000 W) * 100
Efficiency = 50%
Determining the Load for Maximum Efficiency:
To determine the load at which the efficiency is maximum, we need to calculate the efficiency at different loads and compare them.
Let's assume the load on the transformer is x kVA.
Output Power = Copper losses + Constant losses
Output Power = 2000 W + 500 W
Output Power = 2500 W
Input Power = Output Power + Copper losses + Constant losses
Input Power = 2500 W + 2000 W + 500 W
Input Power = 5000 W
Efficiency = (Output Power / Input Power) * 100
Efficiency = (2500 W / 5000 W) * 100
Efficiency = 50%
We can observe that the efficiency remains constant at 50% for any load on the transformer. Therefore, the efficiency is maximum at any load.
Conclusion:
The maximum efficiency of the transformer is achieved at any load. The correct answer is option 'A' - 250 kVA.
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A 500 kVA transformer has constant loss of 500 W and copper losses at full load are 2,000 W.Then at what load, is the efficiency maximum ?a)250 kVAb)500 kVAc)1000 kVAd)125 kVACorrect answer is option 'A'. Can you explain this answer?
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