Prove that 1/root 3 is an irrational. Give me ans fast it's urgent?

Question

Answer

Let, take that 1/√3 is rational no.so, we can write this no. as 1/√2 = a/b.....here, a nd b r 2 co- prime no. nd b is not = 0.....multiple bY √3 both side we, get 1= (a√3)/b.....noW, multiply bY bb= a√3divided by a we got ans~~ b/@ = √3here, a nd b r integer so, b/a is rational no. so, √3 should be rational no.but....√3 is irrational no. it contradiCts HENCE, 1/√3 is irrational no.-----cheer'''''''' proved....hope it'll be help U aaisha....

Answer

Answer

Delete ur answer. .....kkRCB defintely won this match hahahahahhhhy i wait nd watch whole moment of rcbian nd result outcome is KKR beat rcb by # 4 wicket hahaha :::  infinite...

Answer

Its mt plea$ur£ g noW entrained the matCh of RCB....kkyehh seen every moment of the ball what would happened end of thi$ match ...............but not cro$$ 200+ hahahahhhahahahahhhhahhahahahahhahhjhahahhhahahhhhhhahahhahahahhrcb pakka yekin h 200+ pr karaga ....what's new about rcb .........normal team aslO reaching 150+ hahahahahah

Answer

Answer

Proof that 1/√3 is irrational:

Assume that 1/√3 is rational, which means it can be expressed as a fraction of two integers a and b such that a/b is in the lowest term.

Squaring both sides:

(1/√3)^2 = (a/b)^2

1/3 = a^2/b^2

Multiplying both sides by b^2:

b^2/3 = a^2

Therefore:

a^2 is divisible by 3. This means that a must be divisible by 3.

Let a = 3k:

(3k)^2 = b^2/3

9k^2 = b^2/3

This implies:

b^2 = 27k^2

Thus:

b^2 is divisible by 3. This means that b must be divisible by 3.

Contradiction:

This contradicts the fact that a/b is in the lowest term since both a and b are divisible by 3, which means they have a common factor of 3.

Conclusion:

Therefore, 1/√3 is irrational since it cannot be expressed as a fraction of two integers in the lowest term.

Answer

Rahyan u worry of ur RR..don't judge my RCB..Rahyan... Mene pc par samjaya hena.. Phir aise harkate kar rhe ho..If ur my bro thn don't comment on my RCB.. If not thn block me r8 now. RR hahaha hahaha hahaha haha haha ha ha ha ha ha ha ha ha ha ha ha ha ha ha ha ha ha ha ha ha ha ha ha ha ha ha ha ha ha ha ha ha ha ha ha ha ha ha ha ha ha.

Answer

Prove by contradiction method

Answer

I know mr

Answer

Thank uh rahyan g... Yaa I can't miss this match

Answer

RCB wins the match

Answer

Let 1/root3 a rational no.=p/q where p and q are co prime integers and q not equal to 0.              then 1/root3 = p /q.         By doing cross multiplication we get.        q= p×root3.         Since p/q is a rational no. and p and q are integers and we know integers are closed with respect to multiplication and subtraction therefore p and q are rational numbers.      We have proved above that q=p×root3.   But q is rational and root3 is irrational.   hence p×root3 is also irrational  and we know that a rational no. cannot be equal to a rational no. so our supposition was wrong hence 1/root3 is an irrational no.

Answer

Yeah #RCB will definitely won.... Let's see. Hey rcb crossed 150Don't laugh rahyan... Nd don't make me angry by saying it's a normal team ohk...... ... Just wait and watch what will happen next

Similar Class 10 Doubts

prove that root 2 isirrational Related: Irrational Numbers (Easy Explanation) - Real Numbers, CBSE, Class 10, Mathematics

Prove that root 3- root 2 is irrational ?

Prove that root 3 - root 8 is an irrational?

Prove that Root 3 is irrational.?

prove that 1/root 2 is irrational

Top Courses for Class 10View all

Science Class 10

Social Studies (SST) Class 10

Mathematics (Maths) Class 10

English Grammar Advanced

English Grammar Basic

Top Courses for Class 10

Top Courses for Class 10

Suggested Free Tests

Related Content

About Class 10

Class 10 Study Material

Class 10 All Subjects

NCERT Textbook Solutions

Other Classes

Important Links

Company