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A fair coin is tossed independently four times. The probability of the event "the number of time heads shown up is more than the number of times tails shown up" is
  • a)
    1/16
  • b)
    1/8
  • c)
    1/4
  • d)
    5/16
Correct answer is option 'D'. Can you explain this answer?
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A fair coin is tossed independently four times. The probability of the...
Here we have to find
P(H,H,H,T) + P(H,H,H,H)
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A fair coin is tossed independently four times. The probability of the...
Here we have to find
P(H,H,H,T) + P(H,H,H,H)
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Community Answer
A fair coin is tossed independently four times. The probability of the...
The probability of the event "heads on the first toss, tails on the second toss, heads on the third toss, and tails on the fourth toss" is 0.5 * 0.5 * 0.5 * 0.5 = 0.0625.
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