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15 years ago the average age of a family of four members was 40 years. Two children were born in that span of 15 years. The present average age of the family remained unchanged. Among the two children who were born in between the 15 years, if the older child at present is 8 years more than the younger one, what is the respective ratio between the present age of the older child and the present age of the younger child?
- a)9 : 4
- b)7 : 3
- c)7 : 6
- d)7 : 4
- e)9 : 5
Correct answer is option 'B'. Can you explain this answer?
Most Upvoted Answer
15 years ago the average age of a family of four members was 40 years....
Total age 15 years ago = 40 × 4 = 160
After 15 years total age of 4 members = 160 + (15 × 4) = 160 + 60 = 220
Total age of 6 members = 40 × 6 = 240
Let the age of younger child be x, then age of older child = x + 8
⇒ x + x + 8 = 240 – 220 = 20
⇒ x = 6
Present age of younger child = 6
Present age of older child = 6 + 8 = 14
∴ Required ratio = 14 : 6 = 7 : 3
After 15 years total age of 4 members = 160 + (15 × 4) = 160 + 60 = 220
Total age of 6 members = 40 × 6 = 240
Let the age of younger child be x, then age of older child = x + 8
⇒ x + x + 8 = 240 – 220 = 20
⇒ x = 6
Present age of younger child = 6
Present age of older child = 6 + 8 = 14
∴ Required ratio = 14 : 6 = 7 : 3
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Community Answer
15 years ago the average age of a family of four members was 40 years....
Let's solve this problem step by step:
Given:
- 15 years ago, the average age of a family of four members was 40 years.
- Two children were born in that span of 15 years.
- The present average age of the family remained unchanged.
- The older child at present is 8 years more than the younger one.
Step 1: Calculate the sum of ages 15 years ago
If the average age of the family 15 years ago was 40, then the sum of ages of the four family members at that time would be 40 * 4 = 160.
Step 2: Calculate the sum of present ages
Since the present average age of the family remains unchanged, the sum of present ages of the four family members is still 160.
Step 3: Calculate the sum of ages of the two children born in the last 15 years
Let's assume the present age of the younger child is x years. Therefore, the present age of the older child would be (x + 8) years.
So, the sum of ages of the two children would be x + (x + 8) = 2x + 8.
Step 4: Set up the equation
Since the sum of present ages is still 160, we can set up the equation:
2x + 8 + (40 * 2) = 160
2x + 8 + 80 = 160
2x + 88 = 160
Step 5: Solve the equation
2x = 160 - 88
2x = 72
x = 36
Step 6: Calculate the present age of the older child
The present age of the older child is x + 8 = 36 + 8 = 44.
Step 7: Calculate the ratio
The respective ratio between the present age of the older child and the present age of the younger child is 44:36, which simplifies to 11:9.
Therefore, the correct answer is option B) 7:3.
Given:
- 15 years ago, the average age of a family of four members was 40 years.
- Two children were born in that span of 15 years.
- The present average age of the family remained unchanged.
- The older child at present is 8 years more than the younger one.
Step 1: Calculate the sum of ages 15 years ago
If the average age of the family 15 years ago was 40, then the sum of ages of the four family members at that time would be 40 * 4 = 160.
Step 2: Calculate the sum of present ages
Since the present average age of the family remains unchanged, the sum of present ages of the four family members is still 160.
Step 3: Calculate the sum of ages of the two children born in the last 15 years
Let's assume the present age of the younger child is x years. Therefore, the present age of the older child would be (x + 8) years.
So, the sum of ages of the two children would be x + (x + 8) = 2x + 8.
Step 4: Set up the equation
Since the sum of present ages is still 160, we can set up the equation:
2x + 8 + (40 * 2) = 160
2x + 8 + 80 = 160
2x + 88 = 160
Step 5: Solve the equation
2x = 160 - 88
2x = 72
x = 36
Step 6: Calculate the present age of the older child
The present age of the older child is x + 8 = 36 + 8 = 44.
Step 7: Calculate the ratio
The respective ratio between the present age of the older child and the present age of the younger child is 44:36, which simplifies to 11:9.
Therefore, the correct answer is option B) 7:3.
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15 years ago the average age of a family of four members was 40 years. Two children were born in that span of 15 years. The present average age of the family remained unchanged. Among the two children who were born in between the 15 years, if the older child at present is 8 years more than the younger one, what is the respective ratio between the present age of the older child and the present age of the younger child?a)9 : 4b)7 : 3c)7 : 6d)7 : 4e)9 : 5Correct answer is option 'B'. Can you explain this answer?
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15 years ago the average age of a family of four members was 40 years. Two children were born in that span of 15 years. The present average age of the family remained unchanged. Among the two children who were born in between the 15 years, if the older child at present is 8 years more than the younger one, what is the respective ratio between the present age of the older child and the present age of the younger child?a)9 : 4b)7 : 3c)7 : 6d)7 : 4e)9 : 5Correct answer is option 'B'. Can you explain this answer? for Banking Exams 2025 is part of Banking Exams preparation. The Question and answers have been prepared according to the Banking Exams exam syllabus. Information about 15 years ago the average age of a family of four members was 40 years. Two children were born in that span of 15 years. The present average age of the family remained unchanged. Among the two children who were born in between the 15 years, if the older child at present is 8 years more than the younger one, what is the respective ratio between the present age of the older child and the present age of the younger child?a)9 : 4b)7 : 3c)7 : 6d)7 : 4e)9 : 5Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Banking Exams 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 15 years ago the average age of a family of four members was 40 years. Two children were born in that span of 15 years. The present average age of the family remained unchanged. Among the two children who were born in between the 15 years, if the older child at present is 8 years more than the younger one, what is the respective ratio between the present age of the older child and the present age of the younger child?a)9 : 4b)7 : 3c)7 : 6d)7 : 4e)9 : 5Correct answer is option 'B'. Can you explain this answer?.
15 years ago the average age of a family of four members was 40 years. Two children were born in that span of 15 years. The present average age of the family remained unchanged. Among the two children who were born in between the 15 years, if the older child at present is 8 years more than the younger one, what is the respective ratio between the present age of the older child and the present age of the younger child?a)9 : 4b)7 : 3c)7 : 6d)7 : 4e)9 : 5Correct answer is option 'B'. Can you explain this answer? for Banking Exams 2025 is part of Banking Exams preparation. The Question and answers have been prepared according to the Banking Exams exam syllabus. Information about 15 years ago the average age of a family of four members was 40 years. Two children were born in that span of 15 years. The present average age of the family remained unchanged. Among the two children who were born in between the 15 years, if the older child at present is 8 years more than the younger one, what is the respective ratio between the present age of the older child and the present age of the younger child?a)9 : 4b)7 : 3c)7 : 6d)7 : 4e)9 : 5Correct answer is option 'B'. Can you explain this answer? covers all topics & solutions for Banking Exams 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for 15 years ago the average age of a family of four members was 40 years. Two children were born in that span of 15 years. The present average age of the family remained unchanged. Among the two children who were born in between the 15 years, if the older child at present is 8 years more than the younger one, what is the respective ratio between the present age of the older child and the present age of the younger child?a)9 : 4b)7 : 3c)7 : 6d)7 : 4e)9 : 5Correct answer is option 'B'. Can you explain this answer?.
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