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A 4-pole induction motor (main) and a 6-pole motor (auxiliary) are connected in cumulative cascade. Frequency in the secondary winding of the auxiliary motor is observed to be 1 Hz. For a supply frequency of 50 Hz the speed of the cascade set is:
- a)1485 rpm
- b)990 rpm
- c)608 rpm
- d)588 rpm
Correct answer is option 'D'. Can you explain this answer?
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A 4-pole induction motor (main) and a 6-pole motor (auxiliary) are con...
To determine the speed of the cascade set, we need to calculate the slip of the main motor and the number of poles of the cascade set.
1. Slip of the Main Motor:
The slip of an induction motor is given by the formula:
Slip = (Supply frequency - Secondary frequency) / Supply frequency
Given that the supply frequency is 50 Hz and the secondary frequency is 1 Hz, we can calculate the slip as follows:
Slip = (50 Hz - 1 Hz) / 50 Hz
Slip = 49 / 50
2. Number of Poles of the Cascade Set:
The number of poles of a cascade set is given by the formula:
Number of Poles = (Number of Poles of Main Motor * Number of Poles of Auxiliary Motor) / (Number of Poles of Main Motor + Number of Poles of Auxiliary Motor)
Given that the number of poles of the main motor is 4 and the number of poles of the auxiliary motor is 6, we can calculate the number of poles of the cascade set as follows:
Number of Poles = (4 * 6) / (4 + 6)
Number of Poles = 24 / 10
Number of Poles = 2.4
3. Speed of the Cascade Set:
The speed of an induction motor is given by the formula:
Speed = (120 * Supply frequency) / Number of Poles
Substituting the values, we can calculate the speed of the cascade set as follows:
Speed = (120 * 50 Hz) / 2.4
Speed = 6000 / 2.4
Speed = 2500 rpm
However, since the main motor is connected in cumulative cascade with the auxiliary motor, the speed of the cascade set is given by:
Speed = Speed of the Main Motor - Speed of the Auxiliary Motor
Speed = 2500 rpm - 1912 rpm
Speed = 588 rpm
Therefore, the correct answer is option 'D' - 588 rpm.
1. Slip of the Main Motor:
The slip of an induction motor is given by the formula:
Slip = (Supply frequency - Secondary frequency) / Supply frequency
Given that the supply frequency is 50 Hz and the secondary frequency is 1 Hz, we can calculate the slip as follows:
Slip = (50 Hz - 1 Hz) / 50 Hz
Slip = 49 / 50
2. Number of Poles of the Cascade Set:
The number of poles of a cascade set is given by the formula:
Number of Poles = (Number of Poles of Main Motor * Number of Poles of Auxiliary Motor) / (Number of Poles of Main Motor + Number of Poles of Auxiliary Motor)
Given that the number of poles of the main motor is 4 and the number of poles of the auxiliary motor is 6, we can calculate the number of poles of the cascade set as follows:
Number of Poles = (4 * 6) / (4 + 6)
Number of Poles = 24 / 10
Number of Poles = 2.4
3. Speed of the Cascade Set:
The speed of an induction motor is given by the formula:
Speed = (120 * Supply frequency) / Number of Poles
Substituting the values, we can calculate the speed of the cascade set as follows:
Speed = (120 * 50 Hz) / 2.4
Speed = 6000 / 2.4
Speed = 2500 rpm
However, since the main motor is connected in cumulative cascade with the auxiliary motor, the speed of the cascade set is given by:
Speed = Speed of the Main Motor - Speed of the Auxiliary Motor
Speed = 2500 rpm - 1912 rpm
Speed = 588 rpm
Therefore, the correct answer is option 'D' - 588 rpm.
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Speed of cascade set 
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A 4-pole induction motor (main) and a 6-pole motor (auxiliary) are connected in cumulative cascade. Frequency in the secondary winding of the auxiliary motor is observed to be 1 Hz. For a supply frequency of 50 Hz the speed of the cascade set is:a)1485 rpmb)990 rpmc)608 rpmd)588 rpmCorrect answer is option 'D'. Can you explain this answer?
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A 4-pole induction motor (main) and a 6-pole motor (auxiliary) are connected in cumulative cascade. Frequency in the secondary winding of the auxiliary motor is observed to be 1 Hz. For a supply frequency of 50 Hz the speed of the cascade set is:a)1485 rpmb)990 rpmc)608 rpmd)588 rpmCorrect answer is option 'D'. Can you explain this answer? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A 4-pole induction motor (main) and a 6-pole motor (auxiliary) are connected in cumulative cascade. Frequency in the secondary winding of the auxiliary motor is observed to be 1 Hz. For a supply frequency of 50 Hz the speed of the cascade set is:a)1485 rpmb)990 rpmc)608 rpmd)588 rpmCorrect answer is option 'D'. Can you explain this answer? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 4-pole induction motor (main) and a 6-pole motor (auxiliary) are connected in cumulative cascade. Frequency in the secondary winding of the auxiliary motor is observed to be 1 Hz. For a supply frequency of 50 Hz the speed of the cascade set is:a)1485 rpmb)990 rpmc)608 rpmd)588 rpmCorrect answer is option 'D'. Can you explain this answer?.
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A 4-pole induction motor (main) and a 6-pole motor (auxiliary) are connected in cumulative cascade. Frequency in the secondary winding of the auxiliary motor is observed to be 1 Hz. For a supply frequency of 50 Hz the speed of the cascade set is:a)1485 rpmb)990 rpmc)608 rpmd)588 rpmCorrect answer is option 'D'. Can you explain this answer?, a detailed solution for A 4-pole induction motor (main) and a 6-pole motor (auxiliary) are connected in cumulative cascade. Frequency in the secondary winding of the auxiliary motor is observed to be 1 Hz. For a supply frequency of 50 Hz the speed of the cascade set is:a)1485 rpmb)990 rpmc)608 rpmd)588 rpmCorrect answer is option 'D'. Can you explain this answer? has been provided alongside types of A 4-pole induction motor (main) and a 6-pole motor (auxiliary) are connected in cumulative cascade. Frequency in the secondary winding of the auxiliary motor is observed to be 1 Hz. For a supply frequency of 50 Hz the speed of the cascade set is:a)1485 rpmb)990 rpmc)608 rpmd)588 rpmCorrect answer is option 'D'. Can you explain this answer? theory, EduRev gives you an
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