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In a vibrating reed type frequency meter, the reed which will vibrate the most is the one whose natural frequency is equal to
- a)four times the frequency of supply
- b)the frequency of supply
- c)twice the frequency of supply
- d)half the frequency of supply
Correct answer is option 'C'. Can you explain this answer?
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In a vibrating reed type frequency meter, the reed which will vibrate ...
Vibrating reed type frequency meter:
- A vibrating-reed frequency meter is a measuring instrument that is used to measure the frequency of various electric circuits.
- Vibrating Reed Frequency meters indicate the supply frequency by means of individual reeds when rated voltage ± 20% is applied across the terminals of the meter.
- It consists of 7 vibrating reeds and each vibrating reed has a specific value.
- These reeds vibrate when this frequency meter is connected to the supply for the measurement of frequency.
- The reed which will vibrate the most is the one whose natural frequency is equal to twice the frequency of the supply.
Features of vibrating reed meter:
- No aging effect
- Faster response
- Lighter in weight
- Low power consumption
- Rugged construction
- High reliability
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In a vibrating reed type frequency meter, the reed which will vibrate ...
Introduction:
A vibrating reed type frequency meter is a device used to measure the frequency of an alternating current (AC) power supply. It consists of a reed or tuning fork that vibrates at a certain frequency when excited by the AC signal. The frequency at which the reed vibrates the most is known as its natural frequency. This natural frequency depends on the physical characteristics of the reed and is independent of the frequency of the AC supply.
Explanation:
The correct answer to the given question is option 'C' - twice the frequency of supply. Let's understand why this is the case.
Resonance:
When an external force is applied to an object at its natural frequency, the object starts to vibrate with maximum amplitude. This phenomenon is known as resonance. In the case of a vibrating reed frequency meter, the reed vibrates the most when the frequency of the AC supply matches its natural frequency.
Relationship between natural frequency and frequency of supply:
The natural frequency of a vibrating reed depends on its physical properties such as length, thickness, and material. It is independent of the frequency of the AC supply. The AC supply frequency only determines how excited the reed becomes and at what frequency it vibrates the most.
Explanation of options:
a) If the natural frequency of the reed is four times the frequency of the supply, it means that the reed will vibrate with maximum amplitude when the supply frequency is one-fourth of its natural frequency. This option is incorrect.
b) If the natural frequency of the reed is equal to the frequency of the supply, it means that the reed will vibrate with maximum amplitude when the supply frequency matches its natural frequency. This option is incorrect.
c) If the natural frequency of the reed is twice the frequency of the supply, it means that the reed will vibrate with maximum amplitude when the supply frequency is half of its natural frequency. This option is correct.
d) If the natural frequency of the reed is half the frequency of the supply, it means that the reed will vibrate with maximum amplitude when the supply frequency is twice of its natural frequency. This option is incorrect.
Conclusion:
In a vibrating reed type frequency meter, the reed that will vibrate the most is the one whose natural frequency is twice the frequency of the supply. This occurs due to the phenomenon of resonance, where an object vibrates with maximum amplitude when excited at its natural frequency.
A vibrating reed type frequency meter is a device used to measure the frequency of an alternating current (AC) power supply. It consists of a reed or tuning fork that vibrates at a certain frequency when excited by the AC signal. The frequency at which the reed vibrates the most is known as its natural frequency. This natural frequency depends on the physical characteristics of the reed and is independent of the frequency of the AC supply.
Explanation:
The correct answer to the given question is option 'C' - twice the frequency of supply. Let's understand why this is the case.
Resonance:
When an external force is applied to an object at its natural frequency, the object starts to vibrate with maximum amplitude. This phenomenon is known as resonance. In the case of a vibrating reed frequency meter, the reed vibrates the most when the frequency of the AC supply matches its natural frequency.
Relationship between natural frequency and frequency of supply:
The natural frequency of a vibrating reed depends on its physical properties such as length, thickness, and material. It is independent of the frequency of the AC supply. The AC supply frequency only determines how excited the reed becomes and at what frequency it vibrates the most.
Explanation of options:
a) If the natural frequency of the reed is four times the frequency of the supply, it means that the reed will vibrate with maximum amplitude when the supply frequency is one-fourth of its natural frequency. This option is incorrect.
b) If the natural frequency of the reed is equal to the frequency of the supply, it means that the reed will vibrate with maximum amplitude when the supply frequency matches its natural frequency. This option is incorrect.
c) If the natural frequency of the reed is twice the frequency of the supply, it means that the reed will vibrate with maximum amplitude when the supply frequency is half of its natural frequency. This option is correct.
d) If the natural frequency of the reed is half the frequency of the supply, it means that the reed will vibrate with maximum amplitude when the supply frequency is twice of its natural frequency. This option is incorrect.
Conclusion:
In a vibrating reed type frequency meter, the reed that will vibrate the most is the one whose natural frequency is twice the frequency of the supply. This occurs due to the phenomenon of resonance, where an object vibrates with maximum amplitude when excited at its natural frequency.
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In a vibrating reed type frequency meter, the reed which will vibrate the most is the one whose natural frequency is equal toa)four times the frequency of supplyb)the frequency of supplyc)twice the frequency of supplyd)half the frequency of supplyCorrect answer is option 'C'. Can you explain this answer?
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