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Prove that√6 is irrational no.?
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Prove that√6 is irrational no.?
Do it by the help of contradiction method...........👉let us suppose that √6 is rational therefore it is in the form of a/bwhere a and b both are integers and they both could not be Even....by squaring both sides 6=a^2/b^26b^2 = a^2let a be any even no. therefore it can be expressed as 2c6b^2=(2c)^26b^2=4c^23b^2=2c^2therefore 3b^2 is also even .....which is not possible.....therefore √6 is irrational number...
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Prove that√6 is irrational no.?
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Prove that√6 is irrational no.?
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