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A solid sphere is given a sharp impulse at it's surface at hight h from center as a consequence it starts moving with linear velocity v and angular velocity 3v/2r. r is radius. The h will be? Can anyone explain this question?
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A solid sphere is given a sharp impulse at it's surface at hight h fr...
Given..w=3v/2r...I=moment of inertia of solid sphre=2/5mr^2According to principle of conservation of momentum 1/2mv^2+1/2Iw^2=mgh1/2mv^2+1/2×2/5mr^2×(3v/2r)^2=mgh1/2v^2+9v^2/20=gh19v^2/20=ghh=19v^2/20g..HOPE U GOT IT..
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A solid sphere is given a sharp impulse at it's surface at hight h fr...
Yeah right
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A solid sphere is given a sharp impulse at it's surface at hight h from center as a consequence it starts moving with linear velocity v and angular velocity 3v/2r. r is radius. The h will be? Can anyone explain this question?
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A solid sphere is given a sharp impulse at it's surface at hight h from center as a consequence it starts moving with linear velocity v and angular velocity 3v/2r. r is radius. The h will be? Can anyone explain this question? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A solid sphere is given a sharp impulse at it's surface at hight h from center as a consequence it starts moving with linear velocity v and angular velocity 3v/2r. r is radius. The h will be? Can anyone explain this question? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A solid sphere is given a sharp impulse at it's surface at hight h from center as a consequence it starts moving with linear velocity v and angular velocity 3v/2r. r is radius. The h will be? Can anyone explain this question?.
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