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The escape velocity of a body on the earth surface is 11.2 km/s. If the same body is projected upward with velocity 22.4 km/s, the velocity of this body at infinite distance from the centre of the earth will be:
  • a)
    11.2√2 km/s
  • b)
    Zero
  • c)
    11.2 km/s
  • d)
    11.2√3 km/s
Correct answer is option 'D'. Can you explain this answer?
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The escape velocity of a body on the earth surface is 11.2km/s. If the...
Given then
V = 2Ve
So,
 
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The escape velocity of a body on the earth surface is 11.2km/s. If the...
The escape velocity of a body on the Earth's surface is the minimum velocity required for the body to escape the gravitational pull of the Earth and never return. It is given by the formula:

\[v_e = \sqrt{\frac{2GM}{R}}\]

Where:
- \(v_e\) is the escape velocity
- \(G\) is the gravitational constant
- \(M\) is the mass of the Earth
- \(R\) is the radius of the Earth

The escape velocity on the Earth's surface is 11.2 km/s. If the same body is projected upward with a velocity of 22.4 km/s, it means that its initial velocity is twice the escape velocity.

When a body is projected upward with a velocity greater than the escape velocity, it will eventually slow down due to the Earth's gravitational pull, but it will never come to a stop or fall back to the Earth. At infinite distance from the center of the Earth, the velocity of the body will approach zero.

Therefore, the velocity of the body at infinite distance from the center of the Earth will be 0 m/s.
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The escape velocity of a body on the earth surface is 11.2km/s. If the same body is projected upward with velocity 22.4km/s, the velocity of this body at infinite distance from the centre of the earth will be:a)11.2√2km/sb)Zeroc)11.2km/sd)11.2√3km/sCorrect answer is option 'D'. Can you explain this answer?
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