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A 25 kVA, 11 kV generator has X = 0.2 pu. Its negative and zero sequence reactance are respectively 0.3 and 0.1 pu. The neutral of the generator is solidly grounded. Determine the subtransient current in the generator and the line-to-line voltages for subtransient conditions when an LG fault occurs at the generator terminals. Assume that before the occurrence of the fault, the generator is operating at no load at rated voltage. Ignore resistances.
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A 25 kVA, 11 kV generator has X = 0.2 pu. Its negative and zero sequen...
Subtransient Current in the Generator:
The subtransient current in the generator can be determined using the formula:

I_subtransient = V / (jX + jX_2 + jX_0)

Where:
V = Rated voltage of the generator
X = Positive sequence reactance of the generator
X_2 = Negative sequence reactance of the generator
X_0 = Zero sequence reactance of the generator

Given data:
V = 11 kV
X = 0.2 pu
X_2 = 0.3 pu
X_0 = 0.1 pu

Substituting the values into the formula:

I_subtransient = 11000 / (j0.2 + j0.3 + j0.1)
= 11000 / j0.6
= -18333.33 A

Therefore, the subtransient current in the generator during an LG fault at the terminals is -18333.33 A.

Line-to-Line Voltages for Subtransient Conditions:
During subtransient conditions, the line-to-line voltages can be determined using the formula:

V_line-line = (1 + Z_2 / Z_1)V_phase-phase

Where:
Z_1 = Positive sequence impedance
Z_2 = Negative sequence impedance
V_phase-phase = Phase-to-phase voltage

Given data:
Z_1 = jX
Z_2 = jX_2
V_phase-phase = V / √3

Substituting the values into the formula:

V_line-line = (1 + j0.3 / j0.2) * (11000 / √3)
= (1 + 1.5) * 6346.2
= 15865.5 V

Therefore, the line-to-line voltages for subtransient conditions during an LG fault at the generator terminals are 15865.5 V.
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A 25 kVA, 11 kV generator has X = 0.2 pu. Its negative and zero sequence reactance are respectively 0.3 and 0.1 pu. The neutral of the generator is solidly grounded. Determine the subtransient current in the generator and the line-to-line voltages for subtransient conditions when an LG fault occurs at the generator terminals. Assume that before the occurrence of the fault, the generator is operating at no load at rated voltage. Ignore resistances.?
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A 25 kVA, 11 kV generator has X = 0.2 pu. Its negative and zero sequence reactance are respectively 0.3 and 0.1 pu. The neutral of the generator is solidly grounded. Determine the subtransient current in the generator and the line-to-line voltages for subtransient conditions when an LG fault occurs at the generator terminals. Assume that before the occurrence of the fault, the generator is operating at no load at rated voltage. Ignore resistances.? for Electrical Engineering (EE) 2024 is part of Electrical Engineering (EE) preparation. The Question and answers have been prepared according to the Electrical Engineering (EE) exam syllabus. Information about A 25 kVA, 11 kV generator has X = 0.2 pu. Its negative and zero sequence reactance are respectively 0.3 and 0.1 pu. The neutral of the generator is solidly grounded. Determine the subtransient current in the generator and the line-to-line voltages for subtransient conditions when an LG fault occurs at the generator terminals. Assume that before the occurrence of the fault, the generator is operating at no load at rated voltage. Ignore resistances.? covers all topics & solutions for Electrical Engineering (EE) 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A 25 kVA, 11 kV generator has X = 0.2 pu. Its negative and zero sequence reactance are respectively 0.3 and 0.1 pu. The neutral of the generator is solidly grounded. Determine the subtransient current in the generator and the line-to-line voltages for subtransient conditions when an LG fault occurs at the generator terminals. Assume that before the occurrence of the fault, the generator is operating at no load at rated voltage. Ignore resistances.?.
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