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Whole circle bearing of a line OA is 60°. The reduced bearing of line AO will be:
- a)N 60° W
- b)S 60° W
- c)S 60° E
- d)S 30° E
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Whole circle bearing of a line OA is 60°. The reduced bearing of l...
To find reduced bearing of AO we will first Determine the Reduced bearing of OA.
Reduced bearing of OA = N 60° E
Now, Reduced bearing of AO = back bearing of OA
Back bearing of OA = 60o + 180o = 240o
Reduced bearing of AO = WCB -180o = 240o -180o = S 60° W
Therefore, Reduced bearing of AO = S 60° W.
Reduced bearing of OA = N 60° E
Now, Reduced bearing of AO = back bearing of OA
Back bearing of OA = 60o + 180o = 240o
Reduced bearing of AO = WCB -180o = 240o -180o = S 60° W
Therefore, Reduced bearing of AO = S 60° W.
Most Upvoted Answer
Whole circle bearing of a line OA is 60°. The reduced bearing of l...
A whole circle bearing is a measure of the direction of a line in relation to the north-south axis. It is expressed as an angle measured clockwise from the north direction.
If the whole circle bearing of line OA is 60, it means that the line is 60 degrees clockwise from the north direction.
If the whole circle bearing of line OA is 60, it means that the line is 60 degrees clockwise from the north direction.
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Whole circle bearing of a line OA is 60°. The reduced bearing of line AO will be:a)N 60° Wb)S 60° Wc)S 60° Ed)S 30° ECorrect answer is option 'B'. Can you explain this answer?
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