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Instead of a metre scale, a cloth merchant uses a faulty 120 cm scale while buying, but uses a faulty 80 cm scale while selling the same cloth. If he offers a discount of 20%, what is his overall profit percentage?
- a)25%
- b)20%
- c)40%
- d)15%
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
Instead of a metre scale, a cloth merchant uses a faulty 120 cm scale ...
Seema saved Rs. 900 in the first 3 months. She must saved Rs. (11400 – 900) = Rs. 10500 in the subsequent months.
The sequence will be of the form: 350 + 400 +……….. n terms = 10500
Solving, we get n = 15
The savings of Rs. 10500 is done in 15 months. Seema saved Rs. 11400 in 15+3 = 18 months.
Hence, option A is the correct answer.
The sequence will be of the form: 350 + 400 +……….. n terms = 10500
Solving, we get n = 15
The savings of Rs. 10500 is done in 15 months. Seema saved Rs. 11400 in 15+3 = 18 months.
Hence, option A is the correct answer.
Most Upvoted Answer
Instead of a metre scale, a cloth merchant uses a faulty 120 cm scale ...
Given Information:
- Seema saves 10% of her income in each of the first three months of her service.
- For every subsequent month, her savings are Rs. 50 more than the savings of the immediate previous month.
- Her joining income was Rs. 3000.
To Find:
Total savings from the start of the service.
Approach:
To find the total savings from the start of the service, we need to calculate the savings for each month and then sum them up.
Calculation:
Month 1:
- Seema saves 10% of her joining income.
- Savings in the first month = 10% of Rs. 3000 = 0.10 * 3000 = Rs. 300
Month 2:
- Seema saves 10% of her income.
- Savings in the second month = 10% of (joining income + savings from the previous month) = 10% of (Rs. 3000 + Rs. 300) = Rs. 330
Month 3:
- Seema saves 10% of her income.
- Savings in the third month = 10% of (joining income + savings from the previous month) = 10% of (Rs. 3000 + Rs. 330) = Rs. 333
Month 4:
- Seema saves Rs. 50 more than the savings of the immediate previous month.
- Savings in the fourth month = Savings from the previous month + Rs. 50 = Rs. 333 + Rs. 50 = Rs. 383
Month 5:
- Seema saves Rs. 50 more than the savings of the immediate previous month.
- Savings in the fifth month = Savings from the previous month + Rs. 50 = Rs. 383 + Rs. 50 = Rs. 433
Month 6:
- Seema saves Rs. 50 more than the savings of the immediate previous month.
- Savings in the sixth month = Savings from the previous month + Rs. 50 = Rs. 433 + Rs. 50 = Rs. 483
Continuing this pattern:
Month 7: Rs. 533
Month 8: Rs. 583
Month 9: Rs. 633
Month 10: Rs. 683
Month 11: Rs. 733
Month 12: Rs. 783
Month 13: Rs. 833
Month 14: Rs. 883
Month 15: Rs. 933
Month 16: Rs. 983
Month 17: Rs. 1033
Month 18: Rs. 1083
Total Savings:
To find the total savings, we add up the savings for each month:
Total savings = Rs. 300 + Rs. 330 + Rs. 333 + Rs. 383 + Rs. 433 + Rs. 483 + Rs. 533 + Rs. 583 + Rs. 633 + Rs. 683 + Rs. 733 + Rs. 783 + Rs. 833 + Rs. 883 + Rs. 933 + Rs. 983 + Rs. 1033
- Seema saves 10% of her income in each of the first three months of her service.
- For every subsequent month, her savings are Rs. 50 more than the savings of the immediate previous month.
- Her joining income was Rs. 3000.
To Find:
Total savings from the start of the service.
Approach:
To find the total savings from the start of the service, we need to calculate the savings for each month and then sum them up.
Calculation:
Month 1:
- Seema saves 10% of her joining income.
- Savings in the first month = 10% of Rs. 3000 = 0.10 * 3000 = Rs. 300
Month 2:
- Seema saves 10% of her income.
- Savings in the second month = 10% of (joining income + savings from the previous month) = 10% of (Rs. 3000 + Rs. 300) = Rs. 330
Month 3:
- Seema saves 10% of her income.
- Savings in the third month = 10% of (joining income + savings from the previous month) = 10% of (Rs. 3000 + Rs. 330) = Rs. 333
Month 4:
- Seema saves Rs. 50 more than the savings of the immediate previous month.
- Savings in the fourth month = Savings from the previous month + Rs. 50 = Rs. 333 + Rs. 50 = Rs. 383
Month 5:
- Seema saves Rs. 50 more than the savings of the immediate previous month.
- Savings in the fifth month = Savings from the previous month + Rs. 50 = Rs. 383 + Rs. 50 = Rs. 433
Month 6:
- Seema saves Rs. 50 more than the savings of the immediate previous month.
- Savings in the sixth month = Savings from the previous month + Rs. 50 = Rs. 433 + Rs. 50 = Rs. 483
Continuing this pattern:
Month 7: Rs. 533
Month 8: Rs. 583
Month 9: Rs. 633
Month 10: Rs. 683
Month 11: Rs. 733
Month 12: Rs. 783
Month 13: Rs. 833
Month 14: Rs. 883
Month 15: Rs. 933
Month 16: Rs. 983
Month 17: Rs. 1033
Month 18: Rs. 1083
Total Savings:
To find the total savings, we add up the savings for each month:
Total savings = Rs. 300 + Rs. 330 + Rs. 333 + Rs. 383 + Rs. 433 + Rs. 483 + Rs. 533 + Rs. 583 + Rs. 633 + Rs. 683 + Rs. 733 + Rs. 783 + Rs. 833 + Rs. 883 + Rs. 933 + Rs. 983 + Rs. 1033
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Community Answer
Instead of a metre scale, a cloth merchant uses a faulty 120 cm scale ...
Seema saved Rs. 900 in the first 3 months. She must saved Rs. (11400 – 900) = Rs. 10500 in the subsequent months.
The sequence will be of the form: 350 + 400 +……….. n terms = 10500
Solving, we get n = 15
The savings of Rs. 10500 is done in 15 months. Seema saved Rs. 11400 in 15+3 = 18 months.
Hence, option A is the correct answer.
The sequence will be of the form: 350 + 400 +……….. n terms = 10500
Solving, we get n = 15
The savings of Rs. 10500 is done in 15 months. Seema saved Rs. 11400 in 15+3 = 18 months.
Hence, option A is the correct answer.
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Instead of a metre scale, a cloth merchant uses a faulty 120 cm scale while buying, but uses a faulty 80 cm scale while selling the same cloth. If he offers a discount of 20%, what is his overall profit percentage?a)25%b)20%c)40%d)15%Correct answer is option 'B'. Can you explain this answer?
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