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The number of solutions of the equation 2x + y = 40 where both x and y are positive integers and x <= y is:
  • a)
    7
  • b)
    14
  • c)
    13
  • d)
    18
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
The number of solutions of the equation 2x + y = 40 where both x and y...
y = 38 => x = 1
y = 36 => x = 2
y = 14 => x = 13
y = 12 => x = 14 => Cases from here are not valid as x > y.
Hence, there are 13 solutions.
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Most Upvoted Answer
The number of solutions of the equation 2x + y = 40 where both x and y...
13 bro just take values of 1 to 13 , you can't take 14 because there y will be great
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Community Answer
The number of solutions of the equation 2x + y = 40 where both x and y...
We can rewrite the given equation as $y = 20 - x$. Since $x$ and $y$ are positive integers, we must have $x \leq 20$. Thus, the possible values of $x$ are 1, 2, 3, $\dots$, 19, 20, for a total of $\boxed{20}$ solutions.
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The number of solutions of the equation 2x + y = 40 where both x and y are positive integers and x <= y is:a)7b)14c)13d)18Correct answer is option 'C'. Can you explain this answer?
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