All Courses
Explore Courses UPSC Exam UPSC Test Series Free Notes EduRev Infinity Get the App Login Join for Free
Sign in Open App
JEE Exam  >  JEE Questions  >  The number of moles of sodium hydroxide prese... Start Learning for Free
SaveJoin the Discussion on the App
The number of moles of sodium hydroxide present in 2.5L and 0.5M aqueous solution is?
Clear all your JEE doubts with EduRev
Most Upvoted Answer
The number of moles of sodium hydroxide present in 2.5L and 0.5M aqueo...
Calculation of Moles of Sodium Hydroxide Present in Aqueous Solution


Given Information:


  • Volume of Solution (V) = 2.5 L

  • Concentration of Solution (C) = 0.5 M



Formula Used:


  • Moles (n) = Concentration (C) x Volume (V)



Calculation:


  • Substitute the given values into the formula

  • n = 0.5 M x 2.5 L

  • n = 1.25 moles



Answer:


  • The number of moles of sodium hydroxide present in 2.5L and 0.5M aqueous solution is 1.25 moles.



Explanation:

Moles of a substance can be calculated by multiplying its concentration (in moles per liter) and volume (in liters). In this problem, the given concentration is 0.5 M (moles per liter) and volume is 2.5 L. By multiplying these values, we get the number of moles of sodium hydroxide present in the solution, which is 1.25 moles.
Community Answer
The number of moles of sodium hydroxide present in 2.5L and 0.5M aqueo...
Molarity = no.of moles of solute/ vol of sol in L here molarity is 0.5 and vol = 2.5L...so i gues u can easily find out no. of moles of NaOH....
Explore Courses for JEE exam

Similar JEE Doubts

Chemical reactions involve interaction of atoms and molecules. A large number of atoms/molecules (approximately 6.023 × 1023) are present in a few grams of any chemical compound varying with their atomic/molecular masses. To handle such large numbers conveniently, the mole concept was introduced.This concept has implications in diverse areas such as analytical chemistry, biochemistry, electrochemistry and radiochemistry. The following example illustrates a typical case, involving chemical/electrochemical reaction, which requires a clear understanding of the mole concept. A 4.0 molar aqueous solution NaCl is prepared and 500 mL of this solution is electrolysed. This leads to the evolution of chlorine gas at one of the electrodes (atomic mass: Na = 23, Hg = 200; 1 Faraday = 96,500 coulombs)If the cathode is a Hg electrode, the maximum weight (g) of amalgam formed from this solution is Correct answer is '446'. Can you explain this answer?

Top Courses for JEEView all

Top Courses for JEE

The number of moles of sodium hydroxide present in 2.5L and 0.5M aqueous solution is?
Question Description
The number of moles of sodium hydroxide present in 2.5L and 0.5M aqueous solution is? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about The number of moles of sodium hydroxide present in 2.5L and 0.5M aqueous solution is? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for The number of moles of sodium hydroxide present in 2.5L and 0.5M aqueous solution is?.
Solutions for The number of moles of sodium hydroxide present in 2.5L and 0.5M aqueous solution is? in English & in Hindi are available as part of our courses for JEE. Download more important topics, notes, lectures and mock test series for JEE Exam by signing up for free.
Here you can find the meaning of The number of moles of sodium hydroxide present in 2.5L and 0.5M aqueous solution is? defined & explained in the simplest way possible. Besides giving the explanation of The number of moles of sodium hydroxide present in 2.5L and 0.5M aqueous solution is?, a detailed solution for The number of moles of sodium hydroxide present in 2.5L and 0.5M aqueous solution is? has been provided alongside types of The number of moles of sodium hydroxide present in 2.5L and 0.5M aqueous solution is? theory, EduRev gives you an ample number of questions to practice The number of moles of sodium hydroxide present in 2.5L and 0.5M aqueous solution is? tests, examples and also practice JEE tests.
Explore Courses for JEE exam

Top Courses for JEE

Explore Courses

Suggested Free Tests

Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
10M+ students study on EduRev
Get App
© EduRev
Education Revolution
Signup to see your scores go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup