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Measurement of power of a 3-phase balanced load is done using the wattmeter method. If the ratio of the wattmeter readings is 2 : 1 then the power factor of the circuit will be:
  • a)
    0.0
  • b)
    1.0
  • c)
    0.5
  • d)
    0.866
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
Measurement of power of a 3-phase balanced load is done using the watt...
Calculation of Power Factor:
1. **Given Data:**
- Ratio of Wattmeter readings = 2 : 1
2. **Formula:**
- Power factor (PF) = cos(θ) = P/S
3. **Explanation:**
- The ratio of the wattmeter readings is directly proportional to the active power (P) in a 3-phase balanced load circuit.
- Let's assume the wattmeter readings are 2W and W (2:1 ratio).
- The total power (S) in a 3-phase circuit is given by S = √3 * V * I, where V is the line voltage and I is the line current.
- Therefore, the power factor (PF) can be calculated as PF = (2W + W) / (√3 * V * I)
- Simplifying the expression, PF = 3W / (√3 * V * I) = 3 / (√3 * V * I / W)
- As per the given ratio, W = 1 and 2W = 2.
- Substituting the values, PF = 3 / (2 * √3 * V * I) = 0.866
4. **Conclusion:**
- The power factor of the circuit is 0.866 (approximately) when the ratio of wattmeter readings is 2 : 1.
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Community Answer
Measurement of power of a 3-phase balanced load is done using the watt...
Concept:
In a two-wattmeter method,
The reading of first wattmeter (W1) = VL IL cos (30 – ϕ)
The reading of second wattmeter (W2) = VL IL cos (30 + ϕ)
Total power in the circuit (P) = W1 + W2
Total reactive power in the circuit Q = √3(W1−W2)
Power factor = cos ϕ

Calculation:
Given that, W1 / W2 = 2 : 1

ϕ = 30° 
cosϕ = 0.866
Important Points
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Measurement of power of a 3-phase balanced load is done using the wattmeter method. If the ratio of the wattmeter readings is 2 : 1 then the power factor of the circuit will be:a)0.0b)1.0c)0.5d)0.866Correct answer is option 'D'. Can you explain this answer?
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