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In the following a.c. circuit R = 100000, C = 0.32µF, the frequency of the voltage(f) 50Hz and the root mean = square value of V(t) = 100V. The average power absorbed by the resistor is nearest to?
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In the following a.c. circuit R = 100000, C = 0.32µF, the frequency of...
Given Data:
R = 100000 Ω
C = 0.32 µF
f = 50 Hz
V(t) = 100 V (root mean square value)
Calculating the Impedance:
The impedance (Z) of the circuit can be calculated using the formula:
Z = √(R^2 + (1/(ωC))^2)
Where ω = 2πf is the angular frequency.
Substituting the given values:
ω = 2πf = 2π * 50 = 100π rad/s
Z = √(100000^2 + (1/(100π * 0.32 * 10^(-6)))^2)
Calculating this value gives us the impedance Z ≈ 100000 Ω.
Calculating the Current:
The current (I) flowing through the circuit can be calculated using Ohm's Law:
I = V(t)/Z
Substituting the given values:
I = 100 V / 100000 Ω = 0.001 A
Calculating the Average Power:
The average power (P) absorbed by the resistor can be calculated using the formula:
P = I^2 * R
Substituting the given values:
P = (0.001 A)^2 * 100000 Ω = 0.1 W
Therefore, the average power absorbed by the resistor is approximately 0.1 W.
Explanation:
- The impedance of the circuit is calculated using the formula involving resistance (R), capacitance (C), and angular frequency (ω).
- The current flowing through the circuit is calculated using Ohm's Law, which relates the voltage (V) and impedance (Z).
- Finally, the average power absorbed by the resistor is calculated using the formula involving current (I) and resistance (R).
- The average power absorbed by the resistor in this circuit is approximately 0.1 W.
R = 100000 Ω
C = 0.32 µF
f = 50 Hz
V(t) = 100 V (root mean square value)
Calculating the Impedance:
The impedance (Z) of the circuit can be calculated using the formula:
Z = √(R^2 + (1/(ωC))^2)
Where ω = 2πf is the angular frequency.
Substituting the given values:
ω = 2πf = 2π * 50 = 100π rad/s
Z = √(100000^2 + (1/(100π * 0.32 * 10^(-6)))^2)
Calculating this value gives us the impedance Z ≈ 100000 Ω.
Calculating the Current:
The current (I) flowing through the circuit can be calculated using Ohm's Law:
I = V(t)/Z
Substituting the given values:
I = 100 V / 100000 Ω = 0.001 A
Calculating the Average Power:
The average power (P) absorbed by the resistor can be calculated using the formula:
P = I^2 * R
Substituting the given values:
P = (0.001 A)^2 * 100000 Ω = 0.1 W
Therefore, the average power absorbed by the resistor is approximately 0.1 W.
Explanation:
- The impedance of the circuit is calculated using the formula involving resistance (R), capacitance (C), and angular frequency (ω).
- The current flowing through the circuit is calculated using Ohm's Law, which relates the voltage (V) and impedance (Z).
- Finally, the average power absorbed by the resistor is calculated using the formula involving current (I) and resistance (R).
- The average power absorbed by the resistor in this circuit is approximately 0.1 W.
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In the following a.c. circuit R = 100000, C = 0.32µF, the frequency of the voltage(f) 50Hz and the root mean = square value of V(t) = 100V. The average power absorbed by the resistor is nearest to?
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In the following a.c. circuit R = 100000, C = 0.32µF, the frequency of the voltage(f) 50Hz and the root mean = square value of V(t) = 100V. The average power absorbed by the resistor is nearest to? for Physics 2025 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about In the following a.c. circuit R = 100000, C = 0.32µF, the frequency of the voltage(f) 50Hz and the root mean = square value of V(t) = 100V. The average power absorbed by the resistor is nearest to? covers all topics & solutions for Physics 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In the following a.c. circuit R = 100000, C = 0.32µF, the frequency of the voltage(f) 50Hz and the root mean = square value of V(t) = 100V. The average power absorbed by the resistor is nearest to?.
In the following a.c. circuit R = 100000, C = 0.32µF, the frequency of the voltage(f) 50Hz and the root mean = square value of V(t) = 100V. The average power absorbed by the resistor is nearest to? for Physics 2025 is part of Physics preparation. The Question and answers have been prepared according to the Physics exam syllabus. Information about In the following a.c. circuit R = 100000, C = 0.32µF, the frequency of the voltage(f) 50Hz and the root mean = square value of V(t) = 100V. The average power absorbed by the resistor is nearest to? covers all topics & solutions for Physics 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In the following a.c. circuit R = 100000, C = 0.32µF, the frequency of the voltage(f) 50Hz and the root mean = square value of V(t) = 100V. The average power absorbed by the resistor is nearest to?.
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