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The shear stress developed in lubricating oil, of viscosity 9.81 poise, filled between two parallel plates 1 cm apart and moving with relative velocity of 2 m/s is:
  • a)
    196.2 N/m2
  • b)
    20 N/m2
  • c)
    40 N/m2
  • d)
    29.62 N/m2
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
The shear stress developed in lubricating oil, of viscosity 9.81 poise...
According to Newton’s law of viscosity,  the shear stress is directly proportional to the rate of shear strain or rate of angular deformation of a fluid particle. The fluid particle tends to deform continuously when it is in motion.

Newton’s law of viscosity is a relationship between shear stress and the rate of shear strain.
Given, Viscosity = 9.81 poise = 0.981 Ns/m2 , du= 2 m/s, dy= 1 cm = 1/10-2 m
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The shear stress developed in lubricating oil, of viscosity 9.81 poise, filled between two parallel plates 1 cm apart and moving with relative velocity of 2 m/s is:a)196.2 N/m2b)20 N/m2c)40 N/m2d)29.62 N/m2Correct answer is option 'A'. Can you explain this answer?
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