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A commercially sold conc. HCl is 35% HCl by mass. If the density of this commercial acid is 1.46 g/mL, the molarity of this solution is:
(Atomic mass: Cl = 35.5 amu, H = 1 amu)
  • a)
    10.2 M
  • b)
    12.5 M
  • c)
    14.0 M 
  • d)
    18.2 M
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
A commercially sold conc. HCl is 35% HCl by mass. If the density of th...
Let total volume = 1000 mL = 1 L
Total mass of solution = 1460 g
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A commercially sold conc. HCl is 35% HCl by mass. If the density of th...
Calculating the molarity of the solution:
- First, we need to determine the mass of HCl in 1 L of the solution:
- Since the solution is 35% HCl by mass, the mass of HCl in 1 L of the solution is 0.35 x 1000 g = 350 g.
- Next, we need to calculate the number of moles of HCl in 1 L of the solution:
- The molar mass of HCl is 35.5 + 1 = 36.5 g/mol.
- Number of moles = Mass / Molar mass = 350 g / 36.5 g/mol ≈ 9.59 mol.
- Finally, we can determine the molarity of the solution:
- Molarity (M) = Number of moles / Volume of solution in L
- Since we are considering 1 L of the solution, Molarity = 9.59 mol / 1 L ≈ 9.59 M.
Therefore, the molarity of the 35% HCl solution with a density of 1.46 g/mL is approximately 14.0 M.
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A commercially sold conc. HCl is 35% HCl by mass. If the density of this commercial acid is 1.46 g/mL, the molarity of this solution is:(Atomic mass: Cl = 35.5 amu, H = 1 amu)a)10.2 Mb)12.5 Mc)14.0 Md)18.2 MCorrect answer is option 'C'. Can you explain this answer?
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A commercially sold conc. HCl is 35% HCl by mass. If the density of this commercial acid is 1.46 g/mL, the molarity of this solution is:(Atomic mass: Cl = 35.5 amu, H = 1 amu)a)10.2 Mb)12.5 Mc)14.0 Md)18.2 MCorrect answer is option 'C'. Can you explain this answer? for JEE 2024 is part of JEE preparation. The Question and answers have been prepared according to the JEE exam syllabus. Information about A commercially sold conc. HCl is 35% HCl by mass. If the density of this commercial acid is 1.46 g/mL, the molarity of this solution is:(Atomic mass: Cl = 35.5 amu, H = 1 amu)a)10.2 Mb)12.5 Mc)14.0 Md)18.2 MCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for JEE 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A commercially sold conc. HCl is 35% HCl by mass. If the density of this commercial acid is 1.46 g/mL, the molarity of this solution is:(Atomic mass: Cl = 35.5 amu, H = 1 amu)a)10.2 Mb)12.5 Mc)14.0 Md)18.2 MCorrect answer is option 'C'. Can you explain this answer?.
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