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Let Y denote the number of "head" that occur when two coin are tossed. a. Derive probability distribution of Y. b. Derive the cummulative probability distribution of Y. c. Derive mean and variance of Y.?
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Let Y denote the number of "head" that occur when two coin are tossed....
Probability Distribution of Y:
When two coins are tossed, the possible outcomes for each coin are "head" (H) or "tail" (T). Let's consider the possible outcomes for the two coins together:

- HH (both coins show heads)
- HT (first coin shows heads, second coin shows tails)
- TH (first coin shows tails, second coin shows heads)
- TT (both coins show tails)

The number of "head" occurrences, Y, can take the values 0, 1, or 2 depending on the number of heads obtained.

The probability distribution of Y is as follows:

- P(Y = 0) = P(TT) = 1/4
- P(Y = 1) = P(HT or TH) = 2/4 = 1/2
- P(Y = 2) = P(HH) = 1/4

Cumulative Probability Distribution of Y:
The cumulative probability distribution of Y gives the probability that Y takes on a value less than or equal to a certain value. Let's calculate the cumulative probabilities for each value of Y:

- P(Y ≤ 0) = P(Y = 0) = 1/4
- P(Y ≤ 1) = P(Y = 0) + P(Y = 1) = 1/4 + 1/2 = 3/4
- P(Y ≤ 2) = P(Y = 0) + P(Y = 1) + P(Y = 2) = 1/4 + 1/2 + 1/4 = 1

Mean of Y:
The mean of a probability distribution is the expected value of the random variable. To find the mean of Y, we multiply each possible value of Y by its corresponding probability and sum them up:

- E(Y) = 0 * P(Y = 0) + 1 * P(Y = 1) + 2 * P(Y = 2)
= 0 * 1/4 + 1 * 1/2 + 2 * 1/4
= 0 + 1/2 + 1/2
= 1

Therefore, the mean of Y is 1.

Variance of Y:
The variance of a probability distribution measures the spread of the distribution around the mean. It is calculated using the formula:

- Var(Y) = E((Y - E(Y))^2)

To find the variance of Y, we substitute the values of Y and its corresponding probabilities into the formula:

- Var(Y) = (0 - 1)^2 * P(Y = 0) + (1 - 1)^2 * P(Y = 1) + (2 - 1)^2 * P(Y = 2)
= 1^2 * 1/4 + 0^2 * 1/2 + 1^2 * 1/4
= 1/4 + 0 + 1/4
= 1/2

Therefore, the variance of Y is 1/2.

Summary:
- The probability distribution of Y for two coin tosses is given by P(Y = 0) = 1/4, P(Y = 1) = 1/
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Let Y denote the number of "head" that occur when two coin are tossed. a. Derive probability distribution of Y. b. Derive the cummulative probability distribution of Y. c. Derive mean and variance of Y.?
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