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If AxBy crystallizes in an fcc lattice, with atom A occupying every corner and atom B occupying the center of each face of the unit cell, the correct stoichiometry is
  • a)
    AB3
  • b)
    AB2
  • c)
    A2B
  • d)
    A3B
Correct answer is option 'A'. Can you explain this answer?
Most Upvoted Answer
If AxBycrystallizes in anfcclattice, with atom A occupying every corne...
Explanation:
In a face-centered cubic (fcc) unit cell, there are 8 corners and 6 faces.
Each corner of the unit cell is shared by 8 adjacent unit cells, so each corner atom contributes 1/8 of an atom to a particular unit cell. Since there are 8 corners, this amounts to
8×(1/8) = 1 atom of type A.
Each face of the unit cell is shared by 2 unit cells, so each face-centered atom contributes 1/2 of an atom to a particular unit cell. Since there are 6 faces, this amounts to
6× (1/2) = 3 atoms of type B.
Therefore, the stoichiometry of the compound is AB3, which corresponds to option 1.
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Community Answer
If AxBycrystallizes in anfcclattice, with atom A occupying every corne...
Explanation:

Crystal Structure:
- The crystal structure described in the question is an FCC (face-centered cubic) lattice.
- In an FCC lattice, the atom A occupies every corner of the unit cell, while the atom B occupies the center of each face of the unit cell.

Stoichiometry:
- The stoichiometry of a compound indicates the relative proportions of the elements in the compound.
- In this case, since atom A occupies every corner and atom B occupies the center of each face, the ratio of A to B is 1:2.
- Therefore, the correct stoichiometry for the compound AxBy in an FCC lattice is AB2.

Correct Answer:
- The correct option is 'a) AB2' because the compound has a 1:2 ratio of A to B due to the crystal structure described.
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If AxBycrystallizes in anfcclattice, with atom A occupying every corner and atom B occupying the center of each face of the unit cell, the correct stoichiometry isa)AB3b)AB2c)A2Bd)A3BCorrect answer is option 'A'. Can you explain this answer?
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