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In bacteria, N-formyl methionine is the first amino acid to be incorporated into a polypeptide chain. Accordingly, one would think that all bacterial proteins have a formyl group at their amino acid terminals, and the first amino acid is methionine. however, this is not the case because of the following possible reasons:
A. Deformylase removes the formyl group only during or after the synthesis of polypeptides
B. Aminopeptidase removals only the amino-terminal methionine.
C. Aminopeptidase removes the Amino-terminal As well as one or two additional amino acids
D. Deformylase removes the formal group as well as amino terminal methionine And arts one or two amino acids to it
choose the correct combination from the following
- a)A and B
- b)B and C
- c)A and C
- d)A and D
Correct answer is option 'C'. Can you explain this answer?
Verified Answer
In bacteria, N-formyl methionine is the first amino acid to be incorpo...
Concept:
- The genes in DNA encode protein molecules, which are the "workhorses" of the cell, carrying out all the functions necessary for life.
- In the simplest sense, expressing a gene means manufacturing its corresponding protein, and this multilayered process has two major steps.
- In the first step, the information in DNA is transferred to a messenger RNA (mRNA) molecule by way of a process called transcription.
- During transcription, the DNA of a gene serves as a template for complementary base-pairing, and an enzyme called RNA polymerase II catalyzes the formation of a pre-mRNA molecule, which is then processed to form mature mRNA.
- The resulting mRNA is a single-stranded copy of the gene, which next must be translated into a protein molecule
Explanation:- Although methionine (Met) is the first amino acid incorporated into any new protein, it is not always the first amino acid in mature proteins—in many proteins, methionine is removed after translation.
- In fact, if a large number of proteins are sequenced and compared with their known gene sequences, methionine (or formylmethionine) occurs at the N-terminus of all of them.
- However, not all amino acids are equally likely to occur second in the chain, and the second amino acid influences whether the initial methionine is enzymatically removed.
- In both prokaryotes and eukaryotes, these proteins have the methionine removed so that alanine becomes the N-terminal amino acid.
- Prokaryotic translation begins with N-formylmethionine, and the resulting proteins undergo N-terminal modification to become functionally mature.
- This involves stepwise removal of the N-formyl group catalyzed by PDF, and then the methionine residue through the action of methionine aminopeptidase.
- In most cases N-terminal maturation follows, starting with the removal of the formyl group by the metalloprotease-like enzyme peptide deformylase (PDF).
- Subsequent cleavage of the Met residue is carried out by methionine aminopeptidases (MAP), which are also present in the cytosol.
- In most cases N-terminal maturation follows, starting with the removal of the formyl group by the metalloprotease-like enzyme peptide deformylase (PDF). Subsequent cleavage of the Met residue is carried out by methionine aminopeptidases (MAP), which are also present in the cytosol. The N-terminal maturation pathway of plastids and mitochondria is homologous to that of eubacteria and inherited from the endosymbionts.
Statement A:
Deformylase removes the formyl group only during or after the synthesis of polypeptides
- Consider the explanation above thus this option is true, N-terminal maturation follows, starting with the removal of the formyl group by the metalloprotease-like enzyme peptide deformylase (PDF)
Statement B:
. Aminopeptidase removals only the amino-terminal methionine.
- Consider the explanation above thus this option is not true
Statement A:
Aminopeptidase removes the Amino-terminal as well as one or two additional amino acids
- Consider the explanation above thus this option is true, as the subsequent cleavage of the Met residue is carried out by methionine aminopeptidases (MAP).
Statement A:
Deformylase removes the formal group as well as amino terminal methionine And arts one or two amino acids to it
- Consider the explanation above thus this option is not true
H
ence the correct answer is option 3
Most Upvoted Answer
In bacteria, N-formyl methionine is the first amino acid to be incorpo...
Explanation:
Deformylase removes the formyl group only during or after the synthesis of polypeptides
- Deformylase enzyme is responsible for removing the formyl group from the N-formyl methionine at the beginning of a polypeptide chain.
- This process occurs either during or after the synthesis of polypeptides.
Aminopeptidase removes only the amino-terminal methionine
- Aminopeptidase enzyme is responsible for removing the amino-terminal methionine from a polypeptide chain.
- This enzyme specifically targets the methionine at the amino-terminal end of the polypeptide.
Therefore, the correct combination of reasons for why not all bacterial proteins have a formyl group at their amino acid terminals and the first amino acid is methionine is option C: A and B. This is because deformylase removes the formyl group during or after synthesis, while aminopeptidase removes only the amino-terminal methionine, allowing for variation in the amino acid sequence at the N-terminus of bacterial proteins.
Deformylase removes the formyl group only during or after the synthesis of polypeptides
- Deformylase enzyme is responsible for removing the formyl group from the N-formyl methionine at the beginning of a polypeptide chain.
- This process occurs either during or after the synthesis of polypeptides.
Aminopeptidase removes only the amino-terminal methionine
- Aminopeptidase enzyme is responsible for removing the amino-terminal methionine from a polypeptide chain.
- This enzyme specifically targets the methionine at the amino-terminal end of the polypeptide.
Therefore, the correct combination of reasons for why not all bacterial proteins have a formyl group at their amino acid terminals and the first amino acid is methionine is option C: A and B. This is because deformylase removes the formyl group during or after synthesis, while aminopeptidase removes only the amino-terminal methionine, allowing for variation in the amino acid sequence at the N-terminus of bacterial proteins.
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In bacteria, N-formyl methionine is the first amino acid to be incorporated into a polypeptide chain. Accordingly, one would think that all bacterial proteins have a formyl group at their amino acid terminals, and the first amino acid is methionine. however, this is not the case because of the following possible reasons: A. Deformylase removes the formyl group only during or after the synthesis of polypeptides B. Aminopeptidase removals only the amino-terminal methionine. C. Aminopeptidase removes the Amino-terminal As well as one or two additional amino acids D. Deformylase removes the formal group as well as amino terminal methionine And arts one or two amino acids to it choose the correct combination from the followinga)A and Bb)B and Cc)A and Cd)A and DCorrect answer is option 'C'. Can you explain this answer?
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In bacteria, N-formyl methionine is the first amino acid to be incorporated into a polypeptide chain. Accordingly, one would think that all bacterial proteins have a formyl group at their amino acid terminals, and the first amino acid is methionine. however, this is not the case because of the following possible reasons: A. Deformylase removes the formyl group only during or after the synthesis of polypeptides B. Aminopeptidase removals only the amino-terminal methionine. C. Aminopeptidase removes the Amino-terminal As well as one or two additional amino acids D. Deformylase removes the formal group as well as amino terminal methionine And arts one or two amino acids to it choose the correct combination from the followinga)A and Bb)B and Cc)A and Cd)A and DCorrect answer is option 'C'. Can you explain this answer? for Software Development 2025 is part of Software Development preparation. The Question and answers have been prepared according to the Software Development exam syllabus. Information about In bacteria, N-formyl methionine is the first amino acid to be incorporated into a polypeptide chain. Accordingly, one would think that all bacterial proteins have a formyl group at their amino acid terminals, and the first amino acid is methionine. however, this is not the case because of the following possible reasons: A. Deformylase removes the formyl group only during or after the synthesis of polypeptides B. Aminopeptidase removals only the amino-terminal methionine. C. Aminopeptidase removes the Amino-terminal As well as one or two additional amino acids D. Deformylase removes the formal group as well as amino terminal methionine And arts one or two amino acids to it choose the correct combination from the followinga)A and Bb)B and Cc)A and Cd)A and DCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Software Development 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In bacteria, N-formyl methionine is the first amino acid to be incorporated into a polypeptide chain. Accordingly, one would think that all bacterial proteins have a formyl group at their amino acid terminals, and the first amino acid is methionine. however, this is not the case because of the following possible reasons: A. Deformylase removes the formyl group only during or after the synthesis of polypeptides B. Aminopeptidase removals only the amino-terminal methionine. C. Aminopeptidase removes the Amino-terminal As well as one or two additional amino acids D. Deformylase removes the formal group as well as amino terminal methionine And arts one or two amino acids to it choose the correct combination from the followinga)A and Bb)B and Cc)A and Cd)A and DCorrect answer is option 'C'. Can you explain this answer?.
In bacteria, N-formyl methionine is the first amino acid to be incorporated into a polypeptide chain. Accordingly, one would think that all bacterial proteins have a formyl group at their amino acid terminals, and the first amino acid is methionine. however, this is not the case because of the following possible reasons: A. Deformylase removes the formyl group only during or after the synthesis of polypeptides B. Aminopeptidase removals only the amino-terminal methionine. C. Aminopeptidase removes the Amino-terminal As well as one or two additional amino acids D. Deformylase removes the formal group as well as amino terminal methionine And arts one or two amino acids to it choose the correct combination from the followinga)A and Bb)B and Cc)A and Cd)A and DCorrect answer is option 'C'. Can you explain this answer? for Software Development 2025 is part of Software Development preparation. The Question and answers have been prepared according to the Software Development exam syllabus. Information about In bacteria, N-formyl methionine is the first amino acid to be incorporated into a polypeptide chain. Accordingly, one would think that all bacterial proteins have a formyl group at their amino acid terminals, and the first amino acid is methionine. however, this is not the case because of the following possible reasons: A. Deformylase removes the formyl group only during or after the synthesis of polypeptides B. Aminopeptidase removals only the amino-terminal methionine. C. Aminopeptidase removes the Amino-terminal As well as one or two additional amino acids D. Deformylase removes the formal group as well as amino terminal methionine And arts one or two amino acids to it choose the correct combination from the followinga)A and Bb)B and Cc)A and Cd)A and DCorrect answer is option 'C'. Can you explain this answer? covers all topics & solutions for Software Development 2025 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for In bacteria, N-formyl methionine is the first amino acid to be incorporated into a polypeptide chain. Accordingly, one would think that all bacterial proteins have a formyl group at their amino acid terminals, and the first amino acid is methionine. however, this is not the case because of the following possible reasons: A. Deformylase removes the formyl group only during or after the synthesis of polypeptides B. Aminopeptidase removals only the amino-terminal methionine. C. Aminopeptidase removes the Amino-terminal As well as one or two additional amino acids D. Deformylase removes the formal group as well as amino terminal methionine And arts one or two amino acids to it choose the correct combination from the followinga)A and Bb)B and Cc)A and Cd)A and DCorrect answer is option 'C'. Can you explain this answer?.
Solutions for In bacteria, N-formyl methionine is the first amino acid to be incorporated into a polypeptide chain. Accordingly, one would think that all bacterial proteins have a formyl group at their amino acid terminals, and the first amino acid is methionine. however, this is not the case because of the following possible reasons: A. Deformylase removes the formyl group only during or after the synthesis of polypeptides B. Aminopeptidase removals only the amino-terminal methionine. C. Aminopeptidase removes the Amino-terminal As well as one or two additional amino acids D. Deformylase removes the formal group as well as amino terminal methionine And arts one or two amino acids to it choose the correct combination from the followinga)A and Bb)B and Cc)A and Cd)A and DCorrect answer is option 'C'. Can you explain this answer? in English & in Hindi are available as part of our courses for Software Development.
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In bacteria, N-formyl methionine is the first amino acid to be incorporated into a polypeptide chain. Accordingly, one would think that all bacterial proteins have a formyl group at their amino acid terminals, and the first amino acid is methionine. however, this is not the case because of the following possible reasons: A. Deformylase removes the formyl group only during or after the synthesis of polypeptides B. Aminopeptidase removals only the amino-terminal methionine. C. Aminopeptidase removes the Amino-terminal As well as one or two additional amino acids D. Deformylase removes the formal group as well as amino terminal methionine And arts one or two amino acids to it choose the correct combination from the followinga)A and Bb)B and Cc)A and Cd)A and DCorrect answer is option 'C'. Can you explain this answer?, a detailed solution for In bacteria, N-formyl methionine is the first amino acid to be incorporated into a polypeptide chain. Accordingly, one would think that all bacterial proteins have a formyl group at their amino acid terminals, and the first amino acid is methionine. however, this is not the case because of the following possible reasons: A. Deformylase removes the formyl group only during or after the synthesis of polypeptides B. Aminopeptidase removals only the amino-terminal methionine. C. Aminopeptidase removes the Amino-terminal As well as one or two additional amino acids D. Deformylase removes the formal group as well as amino terminal methionine And arts one or two amino acids to it choose the correct combination from the followinga)A and Bb)B and Cc)A and Cd)A and DCorrect answer is option 'C'. Can you explain this answer? has been provided alongside types of In bacteria, N-formyl methionine is the first amino acid to be incorporated into a polypeptide chain. Accordingly, one would think that all bacterial proteins have a formyl group at their amino acid terminals, and the first amino acid is methionine. however, this is not the case because of the following possible reasons: A. Deformylase removes the formyl group only during or after the synthesis of polypeptides B. Aminopeptidase removals only the amino-terminal methionine. C. Aminopeptidase removes the Amino-terminal As well as one or two additional amino acids D. Deformylase removes the formal group as well as amino terminal methionine And arts one or two amino acids to it choose the correct combination from the followinga)A and Bb)B and Cc)A and Cd)A and DCorrect answer is option 'C'. Can you explain this answer? theory, EduRev gives you an
ample number of questions to practice In bacteria, N-formyl methionine is the first amino acid to be incorporated into a polypeptide chain. Accordingly, one would think that all bacterial proteins have a formyl group at their amino acid terminals, and the first amino acid is methionine. however, this is not the case because of the following possible reasons: A. Deformylase removes the formyl group only during or after the synthesis of polypeptides B. Aminopeptidase removals only the amino-terminal methionine. C. Aminopeptidase removes the Amino-terminal As well as one or two additional amino acids D. Deformylase removes the formal group as well as amino terminal methionine And arts one or two amino acids to it choose the correct combination from the followinga)A and Bb)B and Cc)A and Cd)A and DCorrect answer is option 'C'. Can you explain this answer? tests, examples and also practice Software Development tests.
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