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The sequence {n^√9999} converges to A.0 B.1 C.9999 D.99?
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The sequence {n^√9999} converges to A.0 B.1 C.9999 D.99?
Convergence of the Sequence {n^√9999}
The sequence {n^√9999} can be analyzed to determine its convergence to a specific value.

Understanding the Sequence
The sequence {n^√9999} consists of terms where each term is obtained by raising the index n to the power of the square root of 9999.

Convergence Criteria
To determine the convergence of the sequence, we need to check if the terms in the sequence approach a specific value as n tends to infinity.

Limit Calculation
As n approaches infinity, the square root of 9999 remains constant. Therefore, the sequence converges to a value equal to the square root of 9999 raised to any power, which results in either 0 or 1 depending on the power.

Final Answer
Therefore, the sequence {n^√9999} converges to 1 as n tends to infinity. Hence, the correct answer is B. 1.
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The sequence {n^√9999} converges to A.0 B.1 C.9999 D.99?
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