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In a military camp there is sufficient food supply for 200 soldiers for 40 days. After 10 days, certain number of men join and everyone eats 50% more than earlier. Now the food lasts for another 10 days. How many soldiers joined the camp after 10 days?
- a)150
- b)300
- c)250
- d)200
Correct answer is option 'D'. Can you explain this answer?
Verified Answer
In a military camp there is sufficient food supply for 200 soldiers fo...
Let eating capacity of each soldier initially = 1 unit/day.
Initial food supply = 200 × 1 × 40 = 8000 units.
Supply left after 10 days = 200 × 1 × 30 units.
Let ‘s’ numbers of soldiers joined the camp.
New capacity of each soldier = 1.5 units/day
∴ The remaining supply is consumed by (200 + s) solders in another 10 days.
∴ 200 × 1 × 30 = (200 + s) × 1.5 × 10
⇒ 400 = 200 + s
⇒ s = 200
Hence, option D.
Most Upvoted Answer
In a military camp there is sufficient food supply for 200 soldiers fo...
Initial Scenario:
- Food supply for 200 soldiers for 40 days
- After 10 days, new soldiers join
Given Information:
- After 10 days, everyone eats 50% more than before
- Food lasts for another 10 days
Solution:
Let's assume the initial consumption rate for each soldier was x units per day.
Therefore, for 200 soldiers, the initial consumption per day was 200x units.
After 10 days, the total consumption for the initial 200 soldiers would be 10 * 200x = 2000x units.
Now, let's say y soldiers joined the camp after 10 days.
So, the total number of soldiers becomes 200 + y.
With the new soldiers joining, the consumption rate per day becomes 1.5x units per soldier.
Therefore, for 200 + y soldiers, the new consumption per day becomes (200 + y) * 1.5x = 300x + 1.5yx units.
Given that the food lasts for another 10 days, we can set up the equation:
(2000x) + 10(300x + 1.5yx) = (200 + y) * 40 * 1.5x
Solving the equation, we find that y = 200.
Therefore, 200 soldiers joined the camp after 10 days.
- Food supply for 200 soldiers for 40 days
- After 10 days, new soldiers join
Given Information:
- After 10 days, everyone eats 50% more than before
- Food lasts for another 10 days
Solution:
Let's assume the initial consumption rate for each soldier was x units per day.
Therefore, for 200 soldiers, the initial consumption per day was 200x units.
After 10 days, the total consumption for the initial 200 soldiers would be 10 * 200x = 2000x units.
Now, let's say y soldiers joined the camp after 10 days.
So, the total number of soldiers becomes 200 + y.
With the new soldiers joining, the consumption rate per day becomes 1.5x units per soldier.
Therefore, for 200 + y soldiers, the new consumption per day becomes (200 + y) * 1.5x = 300x + 1.5yx units.
Given that the food lasts for another 10 days, we can set up the equation:
(2000x) + 10(300x + 1.5yx) = (200 + y) * 40 * 1.5x
Solving the equation, we find that y = 200.
Therefore, 200 soldiers joined the camp after 10 days.
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In a military camp there is sufficient food supply for 200 soldiers for 40 days. After 10 days, certain number of men join and everyone eats 50% more than earlier. Now the food lasts for another 10 days. How many soldiers joined the camp after 10 days?a)150b)300c)250d)200Correct answer is option 'D'. Can you explain this answer?
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