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If p : q is the sub duplicate ratio of p–x2 : q–x2 then x2 is
- a)p/p+q
- b)q/p+q
- c)p/p-q
- d)pq/p+q
Correct answer is option 'D'. Can you explain this answer?
Most Upvoted Answer
If p : q is the sub duplicate ratio of p–x2 : q–x2 then x2...
√(p-x2) /(q-x2) = p/q --(1)
[Sub- duplicate ratios of,
a/b= √a/b]
a/b= √a/b]
Squaring both sides eq. -(1) ;
(p-x2) /(q-x2) = p2/ q2
q2( p-x2) = p2(q-x2)
q2 p - q2 x2 = p2 q - p2 x2
X2 ( p2-q2) = pq (p-q)
x2 = pq (p-q) / (p+q) (p-q)
x2 = pq/p+q
Therefore, option (d) none of these is the correct answer.
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Community Answer
If p : q is the sub duplicate ratio of p–x2 : q–x2 then x2...
: q, then it means that the ratio of the larger quantity to the smaller quantity is the same as the ratio of the smaller quantity to their difference. In other words:
p : q = (p+q) : (p-q)
This is also known as the subduplicate ratio or the sub double ratio. To solve for one of the quantities, you can cross-multiply and simplify:
p(p-q) = q(p+q)
p^2 - pq = pq + q^2
p^2 = 2pq + q^2
p^2 - 2pq - q^2 = 0
This is a quadratic equation that can be solved using the quadratic formula:
p = [2q ± √(4q^2 + 4q^2)]/2
p = q ± q√2
So the two possible values for p are q multiplied by the square root of 2, added or subtracted.
p : q = (p+q) : (p-q)
This is also known as the subduplicate ratio or the sub double ratio. To solve for one of the quantities, you can cross-multiply and simplify:
p(p-q) = q(p+q)
p^2 - pq = pq + q^2
p^2 = 2pq + q^2
p^2 - 2pq - q^2 = 0
This is a quadratic equation that can be solved using the quadratic formula:
p = [2q ± √(4q^2 + 4q^2)]/2
p = q ± q√2
So the two possible values for p are q multiplied by the square root of 2, added or subtracted.
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If p : q is the sub duplicate ratio of p–x2 : q–x2 then x2 isa)p/p+qb)q/p+qc)p/p-qd)pq/p+qCorrect answer is option 'D'. Can you explain this answer?
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