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For a bivariate data, sample correlation coefficient is 0.6 and r - PE.546. Find the number of pairs of observation.?
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For a bivariate data, sample correlation coefficient is 0.6 and r - PE...
Given Data:
- Sample correlation coefficient (r) = 0.6
- r - PE = 0.546

Finding the Number of Pairs of Observations:
1. Formula:
- r = n(r - PE) / sqrt(n + (r^2 - 1))
- Where n is the number of pairs of observations
2. Substitute the Given Values:
- 0.6 = n(0.546) / sqrt(n + ((0.6)^2 - 1))
3. Solve for n:
- 0.6 = 0.546n / sqrt(n + 0.36 - 1)
- 0.6 = 0.546n / sqrt(n - 0.64)
- 0.6 = 0.546n / sqrt(n - 0.64)^2
- (0.6 * sqrt(n - 0.64))^2 = 0.546n
- 0.36(n - 0.64) = 0.546n
- 0.36n - 0.23 = 0.546n
- 0.23 = 0.186n
- n ≈ 1.24
4. Conclusion:
- The number of pairs of observations is approximately 1.24. Since the number of pairs must be a whole number, we can round up to 2 pairs.
Therefore, there are 2 pairs of observations in the bivariate data.
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For a bivariate data, sample correlation coefficient is 0.6 and r - PE.546. Find the number of pairs of observation.?
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