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Which alkene gives the same product by the Markownikoff's and anti-Markownikoff's method
- a)α -butylene
- b)Propylene
- c)α -amylene
- d)β -butylene
Correct answer is option 'D'. Can you explain this answer?
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Which alkene gives the same product by the Markownikoffs and anti-Mark...
Explanation:
Markovnikov's Rule:
- According to Markovnikov's rule, the hydrogen atom in a hydrogen halide (HX) adds to the carbon atom of the double bond that has the greater number of hydrogen atoms attached to it.
- The positive part of the HX molecule adds to the carbon atom with more hydrogen atoms bonded to it, while the halide ion adds to the other carbon atom.
Anti-Markovnikov's Rule:
- Anti-Markovnikov addition involves the addition of the hydrogen atom to the carbon atom that already has more hydrogen atoms attached to it.
- This results in the halide ion adding to the carbon atom with fewer hydrogen atoms bonded to it.
Alkene that gives the same product by both methods:
- The alkene that gives the same product by both Markovnikov's and anti-Markovnikov's methods is beta-butylene.
- When beta-butylene undergoes addition of HBr, it gives the same product (2-bromobutane) whether following Markovnikov's or anti-Markovnikov's rule.
- This is because beta-butylene has the same number of hydrogen atoms attached to each carbon atom of the double bond.
Therefore, the correct answer is option 'D' - beta-butylene.
Markovnikov's Rule:
- According to Markovnikov's rule, the hydrogen atom in a hydrogen halide (HX) adds to the carbon atom of the double bond that has the greater number of hydrogen atoms attached to it.
- The positive part of the HX molecule adds to the carbon atom with more hydrogen atoms bonded to it, while the halide ion adds to the other carbon atom.
Anti-Markovnikov's Rule:
- Anti-Markovnikov addition involves the addition of the hydrogen atom to the carbon atom that already has more hydrogen atoms attached to it.
- This results in the halide ion adding to the carbon atom with fewer hydrogen atoms bonded to it.
Alkene that gives the same product by both methods:
- The alkene that gives the same product by both Markovnikov's and anti-Markovnikov's methods is beta-butylene.
- When beta-butylene undergoes addition of HBr, it gives the same product (2-bromobutane) whether following Markovnikov's or anti-Markovnikov's rule.
- This is because beta-butylene has the same number of hydrogen atoms attached to each carbon atom of the double bond.
Therefore, the correct answer is option 'D' - beta-butylene.
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Which alkene gives the same product by the Markownikoffs and anti-Markownikoffs methoda)α -butyleneb)Propylenec)α -amylened)β -butyleneCorrect answer is option 'D'. Can you explain this answer?
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