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Which alkene gives the same product by the Markownikoff's and anti-Markownikoff's method
- a)α -butylene
- b)Propylene
- c)α -amylene
- d)β -butylene
Correct answer is option 'D'. Can you explain this answer?
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Which alkene gives the same product by the Markownikoffs and anti-Mark...
Explanation:
Key Concept:
The Markovnikov's rule states that in the addition of an unsymmetrical reagent to an unsymmetrical alkene, the major product formed is the one where the reagent adds to the carbon with more hydrogen atoms. On the other hand, the anti-Markovnikov's rule states that in the presence of peroxides, the major product formed is the one where the reagent adds to the carbon with fewer hydrogen atoms.
Alkene Structure:
- α-butyrlene: CH₃-CH=CH-CH₃
- Propylene: CH₃-CH=CH₂
- α-amylene: CH₃-CH=CH-CH₂-CH₃
- β-butyrlene: CH₃-CH=CH-CH₃
Analysis:
- In the case of α-butyrlene, the addition of HBr would give different products when following Markovnikov's and anti-Markovnikov's rule.
- Propylene would also result in different products for the two methods due to its unsymmetrical structure.
- α-amylene would lead to different products for Markovnikov's and anti-Markovnikov's rule due to its unsymmetrical nature.
- However, β-butyrlene has a symmetrical structure with the double bond present between two equivalent carbon atoms. Thus, regardless of whether Markovnikov's or anti-Markovnikov's rule is followed, the product obtained will be the same.
Therefore, the alkene that gives the same product by both the Markovnikov's and anti-Markovnikov's methods is β-butyrlene.
Key Concept:
The Markovnikov's rule states that in the addition of an unsymmetrical reagent to an unsymmetrical alkene, the major product formed is the one where the reagent adds to the carbon with more hydrogen atoms. On the other hand, the anti-Markovnikov's rule states that in the presence of peroxides, the major product formed is the one where the reagent adds to the carbon with fewer hydrogen atoms.
Alkene Structure:
- α-butyrlene: CH₃-CH=CH-CH₃
- Propylene: CH₃-CH=CH₂
- α-amylene: CH₃-CH=CH-CH₂-CH₃
- β-butyrlene: CH₃-CH=CH-CH₃
Analysis:
- In the case of α-butyrlene, the addition of HBr would give different products when following Markovnikov's and anti-Markovnikov's rule.
- Propylene would also result in different products for the two methods due to its unsymmetrical structure.
- α-amylene would lead to different products for Markovnikov's and anti-Markovnikov's rule due to its unsymmetrical nature.
- However, β-butyrlene has a symmetrical structure with the double bond present between two equivalent carbon atoms. Thus, regardless of whether Markovnikov's or anti-Markovnikov's rule is followed, the product obtained will be the same.
Therefore, the alkene that gives the same product by both the Markovnikov's and anti-Markovnikov's methods is β-butyrlene.
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Which alkene gives the same product by the Markownikoffs and anti-Markownikoffs methoda)α -butyleneb)Propylenec)α -amylened)β -butyleneCorrect answer is option 'D'. Can you explain this answer?
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