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The number of ways of arranging 5 boys and 5 girls in a queue of infront of each girl number of girls are more than or equal to the number of boys is k, then k/(5!)^2 is?
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The number of ways of arranging 5 boys and 5 girls in a queue of infro...
Explanation:

Arranging the boys and girls:
- There are 5 boys and 5 girls to be arranged in a queue.
- The condition is that in front of each girl, the number of girls must be more than or equal to the number of boys.

Calculating the total number of ways (k):
- Let's first calculate the total number of ways to arrange the boys and girls without any restrictions.
- Total ways = 10! (arranging 10 people)
- Now, we need to subtract the number of ways where the condition is violated.
- If we fix a boy, there are 5! ways to arrange the boys and 5! ways to arrange the girls in front of him.
- So, the number of ways the condition is violated = 5! * 5!
- Therefore, the number of ways the condition is satisfied (k) = Total ways - Violating ways = 10! - 5! * 5!

Calculating k/(5!)^2:
- k = 10! - 5! * 5!
- k = 10! - 5! * 5!
- k = 10 * 9 * 8 * 7 * 6 * 5! - 5! * 5!
- k = 5! * (10 * 9 * 8 * 7 - 5)
- k = 5! * 3025
- k = 5! * 3025
- k/(5!)^2 = 3025
Therefore, k/(5!)^2 = 3025.
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The number of ways of arranging 5 boys and 5 girls in a queue of infront of each girl number of girls are more than or equal to the number of boys is k, then k/(5!)^2 is?
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