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3a) Calculate the safe compressive load on a hallow steel column of one end rigidly fixed and other end hinged with 12 cm external diameter and 8 cm internal diameter and 10 m length. Use Euler's formula with a factor of safety 3 and E = 200 GPa.?
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3a) Calculate the safe compressive load on a hallow steel column of on...
Calculating Safe Compressive Load on a Hollow Steel Column

Given Data:
- External diameter (D) = 12 cm
- Internal diameter (d) = 8 cm
- Length of the column (L) = 10 m
- Factor of safety (FoS) = 3
- Young's modulus of steel (E) = 200 GPa = 200 x 10^9 Pa

Calculating the Effective Length of the Column (Le):
Effective length, Le = Length of the column (L)
Le = 10 m = 1000 cm

Calculating the Slenderness Ratio (λ):
Slenderness ratio, λ = Le / r
where r is the radius of gyration
r = √(D^2 + d^2) / 4
r = √((12^2 + 8^2) / 4) = √(208) ≈ 14.42 cm
λ = 1000 / 14.42 ≈ 69.36

Calculating the Critical Stress (σc):
Critical stress, σc = (π^2 x E) / (λ^2)
σc = (π^2 x 200 x 10^9) / (69.36^2)
σc ≈ 10.17 x 10^9 Pa

Calculating the Safe Load:
Safe load, P = (π^2 x E x I) / (Le)^2
where I is the moment of inertia of the column
I = π/64 x (D^4 - d^4)
I = π/64 x ((12^4 - 8^4) = π/64 x 3136 = 49π cm^4
P = (π^2 x 200 x 10^9 x 49π) / 1000^2
P ≈ 96.4 x 10^6 N

Applying Factor of Safety:
Safe compressive load = P / FoS
Safe compressive load ≈ 96.4 x 10^6 / 3
Safe compressive load ≈ 32.13 x 10^6 N
Therefore, the safe compressive load on the hollow steel column is approximately 32.13 MN.
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3a) Calculate the safe compressive load on a hallow steel column of one end rigidly fixed and other end hinged with 12 cm external diameter and 8 cm internal diameter and 10 m length. Use Euler's formula with a factor of safety 3 and E = 200 GPa.?
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