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A battery of emf 10V has an internal resistance of 1 ohms and is charged by a 150V de supply using a series resistance of 19 ohms. What is the terminal voltage of the battery?
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A battery of emf 10V has an internal resistance of 1 ohms and is charg...
Terminal Voltage Calculation
- The terminal voltage of a battery is the voltage across its terminals when it is connected in a circuit.
- It can be calculated using the formula:
V_terminal = V_emf - I * R_internal
where V_emf is the emf of the battery, I is the current flowing through the circuit, and R_internal is the internal resistance of the battery.
Given Data
- Emf of the battery (V_emf) = 10V
- Internal resistance of the battery (R_internal) = 1 ohm
- Supply voltage = 150V
- Series resistance = 19 ohms
Calculations
- The current flowing through the circuit can be calculated using Ohm's law:
I = (V_supply) / (R_internal + R_series)
where R_series is the series resistance.
- Substituting the given values, we get:
I = 150 / (1 + 19) = 7.5 A
- Now, substitute the values of emf and internal resistance in the formula for terminal voltage:
V_terminal = 10 - 7.5 * 1 = 2.5 V
Conclusion
- Therefore, the terminal voltage of the battery is 2.5V when charged by a 150V supply using a series resistance of 19 ohms.
- The terminal voltage of a battery is the voltage across its terminals when it is connected in a circuit.
- It can be calculated using the formula:
V_terminal = V_emf - I * R_internal
where V_emf is the emf of the battery, I is the current flowing through the circuit, and R_internal is the internal resistance of the battery.
Given Data
- Emf of the battery (V_emf) = 10V
- Internal resistance of the battery (R_internal) = 1 ohm
- Supply voltage = 150V
- Series resistance = 19 ohms
Calculations
- The current flowing through the circuit can be calculated using Ohm's law:
I = (V_supply) / (R_internal + R_series)
where R_series is the series resistance.
- Substituting the given values, we get:
I = 150 / (1 + 19) = 7.5 A
- Now, substitute the values of emf and internal resistance in the formula for terminal voltage:
V_terminal = 10 - 7.5 * 1 = 2.5 V
Conclusion
- Therefore, the terminal voltage of the battery is 2.5V when charged by a 150V supply using a series resistance of 19 ohms.
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A battery of emf 10V has an internal resistance of 1 ohms and is charged by a 150V de supply using a series resistance of 19 ohms. What is the terminal voltage of the battery?
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A battery of emf 10V has an internal resistance of 1 ohms and is charged by a 150V de supply using a series resistance of 19 ohms. What is the terminal voltage of the battery? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about A battery of emf 10V has an internal resistance of 1 ohms and is charged by a 150V de supply using a series resistance of 19 ohms. What is the terminal voltage of the battery? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A battery of emf 10V has an internal resistance of 1 ohms and is charged by a 150V de supply using a series resistance of 19 ohms. What is the terminal voltage of the battery?.
A battery of emf 10V has an internal resistance of 1 ohms and is charged by a 150V de supply using a series resistance of 19 ohms. What is the terminal voltage of the battery? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about A battery of emf 10V has an internal resistance of 1 ohms and is charged by a 150V de supply using a series resistance of 19 ohms. What is the terminal voltage of the battery? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A battery of emf 10V has an internal resistance of 1 ohms and is charged by a 150V de supply using a series resistance of 19 ohms. What is the terminal voltage of the battery?.
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