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The conversion of 2, 3-dibromobutane to 2-butene with Zn is
  • a)
    Redox reaction
  • b)
    α-Elimination
  • c)
    β-Elimination
  • d)
    Both α-elimination and redox reaction
Correct answer is option 'A'. Can you explain this answer?
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The conversion of 2, 3-dibromobutane to 2-butene with Zn isa)Redox rea...
Redox Reaction:
- The conversion of 2, 3-dibromobutane to 2-butene with Zn involves a redox reaction.
- In this reaction, zinc (Zn) acts as a reducing agent by donating electrons to the dibromobutane molecule.
- As a result, the carbon-bromine bonds in dibromobutane are broken, leading to the formation of 2-butene.
- The zinc undergoes oxidation during this process, where it loses electrons to form zinc ions.

Explanation:
- The process of converting 2, 3-dibromobutane to 2-butene with Zn is a redox reaction because there is a transfer of electrons from zinc to the dibromobutane molecule.
- The reduction of the dibromobutane molecule to form 2-butene involves the gain of electrons, while the oxidation of zinc involves the loss of electrons.
- This redox reaction results in the formation of a double bond in 2-butene, leading to the elimination of the bromine atoms from the dibromobutane molecule.
- Therefore, the correct answer to the question is option 'A' - Redox reaction.
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The conversion of 2, 3-dibromobutane to 2-butene with Zn isa)Redox reactionb)α-Eliminationc)β-Eliminationd)Both α-elimination and redox reactionCorrect answer is option 'A'. Can you explain this answer?
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