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An object of size 2.0 cm is placed perpendicular to the principal axis of a concave mirror. The distance
of the object from the mirror equals the radius of curvature. The size of the image will be
- a)0.5 cm
- b)1.5 cm
- c)1.0cm
- d)2.0 cm
Correct answer is option 'D'. Can you explain this answer?
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Verified Answer
An object of size 2.0 cm is placed perpendicular to the principal axis...
The size of the image will be 2.0 cm.
V=U(given)
m=-v/u
m= - 1
m=h`/h
-1=h`/2
h`=-2
h=2cm
V=U(given)
m=-v/u
m= - 1
m=h`/h
-1=h`/2
h`=-2
h=2cm
Most Upvoted Answer
An object of size 2.0 cm is placed perpendicular to the principal axis...
Explanation:
Given, size of object (h1) = 2.0 cm, distance of object (u) = radius of curvature (R)
Using mirror formula, 1/f = 1/u + 1/v where f is the focal length and v is the distance of image from the mirror
As per the question, u = R, so 1/f = 1/R + 1/v
As per mirror formula, magnification (m) = -v/u = -v/R
Now, we can find the focal length using mirror formula and substituting u = R, we get
1/f = 1/R + 1/v
1/f = 2/R
f = R/2
Substituting this value of f in mirror formula, we get
1/u + 1/v = 1/f
1/R + 1/v = 2/R
1/v = 1/R
v = R
Now, we can find the size of the image using the magnification formula
m = -v/u = -R/R = -1
Size of image (h2) = |m| * h1 = 1 * 2.0 cm = 2.0 cm
Therefore, the correct option is D) 2.0 cm.
Given, size of object (h1) = 2.0 cm, distance of object (u) = radius of curvature (R)
Using mirror formula, 1/f = 1/u + 1/v where f is the focal length and v is the distance of image from the mirror
As per the question, u = R, so 1/f = 1/R + 1/v
As per mirror formula, magnification (m) = -v/u = -v/R
Now, we can find the focal length using mirror formula and substituting u = R, we get
1/f = 1/R + 1/v
1/f = 2/R
f = R/2
Substituting this value of f in mirror formula, we get
1/u + 1/v = 1/f
1/R + 1/v = 2/R
1/v = 1/R
v = R
Now, we can find the size of the image using the magnification formula
m = -v/u = -R/R = -1
Size of image (h2) = |m| * h1 = 1 * 2.0 cm = 2.0 cm
Therefore, the correct option is D) 2.0 cm.
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Community Answer
An object of size 2.0 cm is placed perpendicular to the principal axis...
It is clearly mentioned in the question that the distance of the object is equal to the radius of curvature of the concave mirror.
In this case the image formed is of same height as that of object.
So, height of the object =height of an image
=2cm
In this case the image formed is of same height as that of object.
So, height of the object =height of an image
=2cm
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An object of size 2.0 cm is placed perpendicular to the principal axis of a concave mirror. The distanceof the object from the mirror equals the radius of curvature. The size of the image will bea)0.5 cmb)1.5 cmc)1.0cmd)2.0 cmCorrect answer is option 'D'. Can you explain this answer?
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