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Two resistors of resistances R1=300+or-3ohm and R2 =200+or-2ohm are connected in parallel the equivalent resistance of parallel combination with error is?
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Two resistors of resistances R1=300+or-3ohm and R2 =200+or-2ohm are co...
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Calculating Equivalent Resistance of Parallel Combination with Error
- Resistance of Resistor 1 (R1): R1 = 300 ± 3 ohm
- Resistance of Resistor 2 (R2): R2 = 200 ± 2 ohm
- Calculating Equivalent Resistance (Rp) in Parallel:
Rp = (R1 * R2) / (R1 + R2)
- Substitute the given resistor values:
Rp = (300 * 200) / (300 + 200)
Rp = 60000 / 500
Rp = 120 ohm
- Calculating Error in Equivalent Resistance (ΔRp):
ΔRp = Rp * [(ΔR1/R1) + (ΔR2/R2)]
- Substitute the given error values:
ΔRp = 120 * [(3/300) + (2/200)]
ΔRp = 120 * [0.01 + 0.01]
ΔRp = 120 * 0.02
ΔRp = 2.4 ohm
- Equivalent Resistance of Parallel Combination with Error:
Rp = 120 ± 2.4 ohm
Therefore, the equivalent resistance of the parallel combination of resistors R1 and R2 is 120 ± 2.4 ohm.
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Two resistors of resistances R1=300+or-3ohm and R2 =200+or-2ohm are connected in parallel the equivalent resistance of parallel combination with error is?
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