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A body starts from rest and is uniformly accelerated for 30 s. The distance travelled in the first 10 s is x1, next 10 s is x2 and the last 10 s is x3. Then x1:x2:x3 is the same as
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A body starts from rest and is uniformly accelerated for 30 s. The dis...
Explanation of x1:x2:x3 ratio when a body starts from rest and is uniformly accelerated for 30 s



  • Uniform acceleration: When a body starts from rest and is uniformly accelerated for 30 seconds, it means that the acceleration of the body remains constant for the entire duration of 30 seconds.

  • Formula: The formula for distance travelled by an object with uniform acceleration is given by s = ut + 1/2at^2, where s is the distance travelled, u is the initial velocity, a is the acceleration, and t is the time taken.

  • x1: The distance travelled in the first 10 seconds can be calculated using the above formula by substituting u=0, a=constant acceleration and t=10 seconds.

  • x2: The distance travelled in the next 10 seconds can be calculated using the same formula by substituting u=0, a=constant acceleration and t=10 seconds, but since the body already has a velocity after the first 10 seconds, we need to add the distance travelled during the first 10 seconds to get the total distance travelled in the first 20 seconds.

  • x3: The distance travelled in the last 10 seconds can be calculated using the same formula by substituting u=initial velocity after 20 seconds, a=constant acceleration and t=10 seconds, but since the body already has a velocity after the first 20 seconds, we need to add the distance travelled during the first 20 seconds to get the total distance travelled in the first 30 seconds.

  • Ratio: The ratio x1:x2:x3 can be simplified using the formula for s mentioned earlier. We get:


  • x1 : x2 : x3 = (1/2)a(10)^2 : (1/2)a(10)^2 + 10ua : (1/2)a(10)^2 + 10ua + u(10)^2


  • On simplifying this ratio, we get:


  • x1 : x2 : x3 = 1 : 3 : 5


  • Therefore, the ratio of distances travelled in the first 10 seconds, second 10 seconds and last 10 seconds is 1:3:5 respectively.

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A body starts from rest and is uniformly accelerated for 30 s. The dis...
Is the answer is 1:2:3..
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A body starts from rest and is uniformly accelerated for 30 s. The distance travelled in the first 10 s is x1, next 10 s is x2 and the last 10 s is x3. Then x1:x2:x3 is the same as
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