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When positive integer y is added to each of the first n non-negative integers, which of the following statements is true?
I. If the median of the resulting numbers is   then n is odd
II. The arithmetic mean of the resulting numbers is equal to the median of the resulting numbers
III. The arithmetic mean of the resulting numbers is y units greater than the arithmetic mean of the first n positive integers.
  • a)
    I only
  • b)
    II only
  • c)
    III only
  • d)
    I, II and III
  • e)
    None of the above
Correct answer is option 'B'. Can you explain this answer?
Verified Answer
When positive integer y is added to each of the first n non-negative i...
Given:
  • The list of first n non-negative integers: {0, 1, 2, 3, . . . , n – 1}
  • Positive integer y is added to each integer in this list: {0 + y, 1 + y, 2 + y, . . . n – 1 + y}
    • = {y, y + 1, y + 2, . . . , y + n – 1}
To Find: Which of the 3 statements is/are true?
Approach:
  1. Since these 3 statements deal with:
    • Mean of the first n positive integers
    • Mean of the resulting numbers
    • And, Median of the resulting numbers,
We will first find the expressions for these 3 quantities.
2. Then, we’ll evaluate the 3 statements one by one to determine which is/are true for all values of y and n
Working out:
  • Finding the expressions for the 3 quantities featured in Statements I – III
     
    • Finding Mean of the first n positive integers
      • Sum of first n positive integers = 
      • So, the mean of the first n positive integers =  
        • (n+2/2)
  • Finding Mean of the Resulting Numbers
    • The resulting numbers are: {y, y + 1, y + 2, . . . , y + n – 1}
      • These numbers form an increasing arithmetic sequence of n terms.
        • First term of the sequence = y
        • Last term of the sequence = y + n -1
        • So, the sum of these numbers =
 
  • Finding Median of the Resulting Numbers
    • The resulting numbers are: {y, y + 1, y + 2, . . . , y + n – 1}
    • The total number of elements in this set is (y + n – 1) – y + 1 = n
      • These numbers form an increasing arithmetic sequence of n terms.
      • Now, in an ordered list that has:
        • An even number of elements (say 4 elements), the median of the list is equal to the average of the middle 2 elements of the list
        • An odd number of elements (Say 5 elements), the median of the list is equal to the middle element in the list
 
  • Case 1: If n is odd,
  • Then, Median = the middle element in the list of resulting numbers
  • The first term in the list is y + 0 and the last term is y +(n – 1)
  • So, the Median = 
  • (Note: If the above expression for the Median is not intuitive to you, you can arrive at it by taking a few easy values of n. For example:
    • If n = 3, the list is {y, y + 1, y + 2}. So, the median = y + 1
    • If n = 5, the list is {y, y + 1. y + 2, y + 3, y + 4}. So, the median = y + 2
    • Similarly, if n = 7, the list goes from y to y + 6 and the median = y + 3
    • From these examples, the pattern for how the value of Median changes with n becomes easy to see)
  • Case 2: If n is even,
    • This means, the median of the list is equal to the​
 
  • Evaluating Statement I
    • If the median of the resulting numbers is then n is odd
    • In our calculation of the Median of the Resulting Numbers, observe that the median is always equal to  , whether n is even or odd.
    • Therefore, Statement I is not correct
  • Evaluating Statement II
    • The arithmetic mean of the resulting numbers is equal to the median of the resulting numbers
      • From our calculations of the Mean and Median of the Resulting Numbers, we see that:
        • Mean of the Resulting numbers =
        • Median =
    • So, Statement II is indeed true.
  • Evaluating Statement III
    • The arithmetic mean of the resulting numbers is y units greater than the arithmetic mean of the first n positive integers.
    • From our calculations above, we see that:
      • Mean of the Resulting numbers = 
      • Mean of the first n positive integers 
    • Note that  is not equal to  . Therefore, it is wrong to say that Mean of the Resulting Numbers is y units greater than the Mean of the first n positive integers.
    • So, Statement III is not true.
 
  • Getting to the answer
    • Of the 3 statements, we see that only Statement II is true.
Looking at the answer choices, we see that the correct answer is Option B
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Most Upvoted Answer
When positive integer y is added to each of the first n non-negative i...
Given:
  • The list of first n non-negative integers: {0, 1, 2, 3, . . . , n – 1}
  • Positive integer y is added to each integer in this list: {0 + y, 1 + y, 2 + y, . . . n – 1 + y}
    • = {y, y + 1, y + 2, . . . , y + n – 1}
To Find: Which of the 3 statements is/are true?
Approach:
  1. Since these 3 statements deal with:
    • Mean of the first n positive integers
    • Mean of the resulting numbers
    • And, Median of the resulting numbers,
We will first find the expressions for these 3 quantities.
2. Then, we’ll evaluate the 3 statements one by one to determine which is/are true for all values of y and n
Working out:
  • Finding the expressions for the 3 quantities featured in Statements I – III
     
    • Finding Mean of the first n positive integers
      • Sum of first n positive integers = 
      • So, the mean of the first n positive integers =  
        • (n+2/2)
  • Finding Mean of the Resulting Numbers
    • The resulting numbers are: {y, y + 1, y + 2, . . . , y + n – 1}
      • These numbers form an increasing arithmetic sequence of n terms.
        • First term of the sequence = y
        • Last term of the sequence = y + n -1
        • So, the sum of these numbers =
 
  • Finding Median of the Resulting Numbers
    • The resulting numbers are: {y, y + 1, y + 2, . . . , y + n – 1}
    • The total number of elements in this set is (y + n – 1) – y + 1 = n
      • These numbers form an increasing arithmetic sequence of n terms.
      • Now, in an ordered list that has:
        • An even number of elements (say 4 elements), the median of the list is equal to the average of the middle 2 elements of the list
        • An odd number of elements (Say 5 elements), the median of the list is equal to the middle element in the list
 
  • Case 1: If n is odd,
  • Then, Median = the middle element in the list of resulting numbers
  • The first term in the list is y + 0 and the last term is y +(n – 1)
  • So, the Median = 
  • (Note: If the above expression for the Median is not intuitive to you, you can arrive at it by taking a few easy values of n. For example:
    • If n = 3, the list is {y, y + 1, y + 2}. So, the median = y + 1
    • If n = 5, the list is {y, y + 1. y + 2, y + 3, y + 4}. So, the median = y + 2
    • Similarly, if n = 7, the list goes from y to y + 6 and the median = y + 3
    • From these examples, the pattern for how the value of Median changes with n becomes easy to see)
  • Case 2: If n is even,
    • This means, the median of the list is equal to the​
 
  • Evaluating Statement I
    • If the median of the resulting numbers is then n is odd
    • In our calculation of the Median of the Resulting Numbers, observe that the median is always equal to  , whether n is even or odd.
    • Therefore, Statement I is not correct
  • Evaluating Statement II
    • The arithmetic mean of the resulting numbers is equal to the median of the resulting numbers
      • From our calculations of the Mean and Median of the Resulting Numbers, we see that:
        • Mean of the Resulting numbers =
        • Median =
    • So, Statement II is indeed true.
  • Evaluating Statement III
    • The arithmetic mean of the resulting numbers is y units greater than the arithmetic mean of the first n positive integers.
    • From our calculations above, we see that:
      • Mean of the Resulting numbers = 
      • Mean of the first n positive integers 
    • Note that  is not equal to  . Therefore, it is wrong to say that Mean of the Resulting Numbers is y units greater than the Mean of the first n positive integers.
    • So, Statement III is not true.
 
  • Getting to the answer
    • Of the 3 statements, we see that only Statement II is true.
Looking at the answer choices, we see that the correct answer is Option B
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Community Answer
When positive integer y is added to each of the first n non-negative i...
Given:
  • The list of first n non-negative integers: {0, 1, 2, 3, . . . , n – 1}
  • Positive integer y is added to each integer in this list: {0 + y, 1 + y, 2 + y, . . . n – 1 + y}
    • = {y, y + 1, y + 2, . . . , y + n – 1}
To Find: Which of the 3 statements is/are true?
Approach:
  1. Since these 3 statements deal with:
    • Mean of the first n positive integers
    • Mean of the resulting numbers
    • And, Median of the resulting numbers,
We will first find the expressions for these 3 quantities.
2. Then, we’ll evaluate the 3 statements one by one to determine which is/are true for all values of y and n
Working out:
  • Finding the expressions for the 3 quantities featured in Statements I – III
     
    • Finding Mean of the first n positive integers
      • Sum of first n positive integers = 
      • So, the mean of the first n positive integers =  
        • (n+2/2)
  • Finding Mean of the Resulting Numbers
    • The resulting numbers are: {y, y + 1, y + 2, . . . , y + n – 1}
      • These numbers form an increasing arithmetic sequence of n terms.
        • First term of the sequence = y
        • Last term of the sequence = y + n -1
        • So, the sum of these numbers =
 
  • Finding Median of the Resulting Numbers
    • The resulting numbers are: {y, y + 1, y + 2, . . . , y + n – 1}
    • The total number of elements in this set is (y + n – 1) – y + 1 = n
      • These numbers form an increasing arithmetic sequence of n terms.
      • Now, in an ordered list that has:
        • An even number of elements (say 4 elements), the median of the list is equal to the average of the middle 2 elements of the list
        • An odd number of elements (Say 5 elements), the median of the list is equal to the middle element in the list
 
  • Case 1: If n is odd,
  • Then, Median = the middle element in the list of resulting numbers
  • The first term in the list is y + 0 and the last term is y +(n – 1)
  • So, the Median = 
  • (Note: If the above expression for the Median is not intuitive to you, you can arrive at it by taking a few easy values of n. For example:
    • If n = 3, the list is {y, y + 1, y + 2}. So, the median = y + 1
    • If n = 5, the list is {y, y + 1. y + 2, y + 3, y + 4}. So, the median = y + 2
    • Similarly, if n = 7, the list goes from y to y + 6 and the median = y + 3
    • From these examples, the pattern for how the value of Median changes with n becomes easy to see)
  • Case 2: If n is even,
    • This means, the median of the list is equal to the​
 
  • Evaluating Statement I
    • If the median of the resulting numbers is then n is odd
    • In our calculation of the Median of the Resulting Numbers, observe that the median is always equal to  , whether n is even or odd.
    • Therefore, Statement I is not correct
  • Evaluating Statement II
    • The arithmetic mean of the resulting numbers is equal to the median of the resulting numbers
      • From our calculations of the Mean and Median of the Resulting Numbers, we see that:
        • Mean of the Resulting numbers =
        • Median =
    • So, Statement II is indeed true.
  • Evaluating Statement III
    • The arithmetic mean of the resulting numbers is y units greater than the arithmetic mean of the first n positive integers.
    • From our calculations above, we see that:
      • Mean of the Resulting numbers = 
      • Mean of the first n positive integers 
    • Note that  is not equal to  . Therefore, it is wrong to say that Mean of the Resulting Numbers is y units greater than the Mean of the first n positive integers.
    • So, Statement III is not true.
 
  • Getting to the answer
    • Of the 3 statements, we see that only Statement II is true.
Looking at the answer choices, we see that the correct answer is Option B
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When positive integer y is added to each of the first n non-negative integers, which of the following statements is true?I. If the median of the resulting numbers is then n is oddII. The arithmetic mean of the resulting numbers is equal to the median of the resulting numbersIII. The arithmetic mean of the resulting numbers is y units greater than the arithmetic mean of the first n positive integers.a)I onlyb)II onlyc)III onlyd)I, II and IIIe)None of the aboveCorrect answer is option 'B'. Can you explain this answer?
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