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Consider R² with the usual topology and A,B subset or equal R² then check int(A union B)=int(A) union int(B)?
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Consider R² with the usual topology and A,B subset or equal R² then ch...
Intuition:
The interior of a set represents all the points inside the set that do not touch the boundary. In the case of the union of two sets, the interior will include points that are in the interior of either set.

Verification:

Claim:
int(A ∪ B) = int(A) ∪ int(B)

Proof:

1. Inclusion of int(A ∪ B) in int(A) ∪ int(B):
- Let x be an element of int(A ∪ B). This means that there exists an open ball around x contained entirely within A ∪ B.
- Since x is in A ∪ B, it must be in either A or B. Without loss of generality, assume x is in A.
- Then, the open ball around x is entirely contained within A, making x an interior point of A. Thus, x is in int(A).
- Therefore, int(A ∪ B) is a subset of int(A).

2. Inclusion of int(A) ∪ int(B) in int(A ∪ B):
- Let x be an element of int(A) ∪ int(B). This means that x is either in int(A) or int(B).
- If x is in int(A), there exists an open ball around x contained entirely within A. Since A is a subset of A ∪ B, this open ball is also contained in A ∪ B.
- Similarly, if x is in int(B), there exists an open ball around x contained entirely within B, and hence in A ∪ B.
- Therefore, x is in int(A ∪ B), implying int(A) ∪ int(B) is a subset of int(A ∪ B).

Conclusion:
- Combining both inclusions, we have int(A ∪ B) = int(A) ∪ int(B).
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Consider R² with the usual topology and A,B subset or equal R² then check int(A union B)=int(A) union int(B)?
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