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(From electron transition) The shortest wavelength of He+ in Balmer series is x, then longest wavelength in the Paschene series of Li²+ will be?
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(From electron transition) The shortest wavelength of He+ in Balmer se...
Shortest Wavelength of He+ in Balmer Series:
The shortest wavelength in the Balmer series of He+ corresponds to the transition from n=3 to n=2 energy levels. Let's denote the wavelength as x.

Longest Wavelength in the Paschen Series of Li²+:
To find the longest wavelength in the Paschen series of Li²+, we need to consider transitions to the n=3 energy level. The longest wavelength in the Paschen series can be calculated using the formula:
1/λ = R ((1/3²) - (1/n²))
where R is the Rydberg constant and n is the energy level. For Li²+, n=3.

Calculation:
1/λ = R ((1/3²) - (1/3²))
1/λ = R (1/9 - 1/9)
1/λ = 0
Therefore, the longest wavelength in the Paschen series of Li²+ is infinity. This means that there is no upper limit to the wavelength in the Paschen series of Li²+, as the transition to the n=3 level will result in an infinitely long wavelength.
In conclusion, the longest wavelength in the Paschen series of Li²+ is infinite, in contrast to the finite value of the shortest wavelength in the Balmer series of He+.
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(From electron transition) The shortest wavelength of He+ in Balmer series is x, then longest wavelength in the Paschene series of Li²+ will be?
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