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If three vectors of equal magnitudes 5N and they are inclined with each other at an angle of 120degrees.Then find the magnitude of the resultant vector.?
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If three vectors of equal magnitudes 5N and they are inclined with eac...
Given Information:
- Magnitude of each vector = 5N
- Angle between each vector = 120 degrees

Finding the Resultant Vector:

Step 1: Finding the Components of the Vectors
- Let's assume the vectors are A, B, and C.
- The components of each vector in the x-direction will be 5 * cos(120) = -2.5N.
- The components of each vector in the y-direction will be 5 * sin(120) = 4.33N.

Step 2: Summing the Components
- Summing the x-components of the vectors, we get -2.5N + (-2.5N) + (-2.5N) = -7.5N.
- Summing the y-components of the vectors, we get 4.33N + 4.33N + 4.33N = 12.99N.

Step 3: Finding the Resultant Vector
- Using the components calculated above (-7.5N, 12.99N), we can find the magnitude of the resultant vector using Pythagoras theorem.
- Magnitude of the resultant vector = sqrt((-7.5)^2 + (12.99)^2) = sqrt(56.25 + 168.53) = sqrt(224.78) = 14.99N.
Therefore, the magnitude of the resultant vector when three vectors of equal magnitudes 5N are inclined with each other at an angle of 120 degrees is 14.99N.
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If three vectors of equal magnitudes 5N and they are inclined with each other at an angle of 120degrees.Then find the magnitude of the resultant vector.?
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