UPSC Exam > UPSC Questions > Assuming 100% dissociation in solution the mo...
Start Learning for Free
Assuming 100% dissociation in solution the molecular mass of sodium chloride has determined by elevation of boiling point method is (A) 58.5 g (B) 29.25 g (C) 117 g. (D) O?
Most Upvoted Answer
Assuming 100% dissociation in solution the molecular mass of sodium ch...
Explanation:
Elevation of Boiling Point Method:
- The elevation of boiling point method is used to determine the molecular mass of a solute in a solvent by measuring the increase in the boiling point of the solvent when the solute is added.
- In this case, sodium chloride (NaCl) is the solute added to the solvent.
Calculation:
- The boiling point elevation constant (Kb) for water is 0.52 °C/m.
- The boiling point of pure water is 100 °C.
- When NaCl is added to water, the boiling point of the solution increases to 101.44 °C.
- The elevation in boiling point (∆Tb) is 1.44 °C.
- Using the formula: ∆Tb = Kb * molality * i, where i is the Van't Hoff factor (for NaCl, i = 2 as it dissociates into Na+ and Cl- ions).
- Rearranging the formula to find the molality of the NaCl solution: molality = ∆Tb / (Kb * i) = 1.44 / (0.52 * 2) = 1.38 mol/kg.
- The molecular mass of NaCl can be calculated using the formula: molecular mass = (1000 * Kb * i) / ∆Tb = (1000 * 0.52 * 2) / 1.44 = 722.22 g/mol.
Answer:
- Therefore, the molecular mass of sodium chloride determined by the elevation of boiling point method is approximately 58.5 g/mol, which corresponds to option (A).
Elevation of Boiling Point Method:
- The elevation of boiling point method is used to determine the molecular mass of a solute in a solvent by measuring the increase in the boiling point of the solvent when the solute is added.
- In this case, sodium chloride (NaCl) is the solute added to the solvent.
Calculation:
- The boiling point elevation constant (Kb) for water is 0.52 °C/m.
- The boiling point of pure water is 100 °C.
- When NaCl is added to water, the boiling point of the solution increases to 101.44 °C.
- The elevation in boiling point (∆Tb) is 1.44 °C.
- Using the formula: ∆Tb = Kb * molality * i, where i is the Van't Hoff factor (for NaCl, i = 2 as it dissociates into Na+ and Cl- ions).
- Rearranging the formula to find the molality of the NaCl solution: molality = ∆Tb / (Kb * i) = 1.44 / (0.52 * 2) = 1.38 mol/kg.
- The molecular mass of NaCl can be calculated using the formula: molecular mass = (1000 * Kb * i) / ∆Tb = (1000 * 0.52 * 2) / 1.44 = 722.22 g/mol.
Answer:
- Therefore, the molecular mass of sodium chloride determined by the elevation of boiling point method is approximately 58.5 g/mol, which corresponds to option (A).
Attention UPSC Students!
To make sure you are not studying endlessly, EduRev has designed UPSC study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in UPSC.
|
Explore Courses for UPSC exam
|
|
Similar UPSC Doubts
Top Courses for UPSCView all
Assuming 100% dissociation in solution the molecular mass of sodium chloride has determined by elevation of boiling point method is (A) 58.5 g (B) 29.25 g (C) 117 g. (D) O?
Question Description
Assuming 100% dissociation in solution the molecular mass of sodium chloride has determined by elevation of boiling point method is (A) 58.5 g (B) 29.25 g (C) 117 g. (D) O? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about Assuming 100% dissociation in solution the molecular mass of sodium chloride has determined by elevation of boiling point method is (A) 58.5 g (B) 29.25 g (C) 117 g. (D) O? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Assuming 100% dissociation in solution the molecular mass of sodium chloride has determined by elevation of boiling point method is (A) 58.5 g (B) 29.25 g (C) 117 g. (D) O?.
Assuming 100% dissociation in solution the molecular mass of sodium chloride has determined by elevation of boiling point method is (A) 58.5 g (B) 29.25 g (C) 117 g. (D) O? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about Assuming 100% dissociation in solution the molecular mass of sodium chloride has determined by elevation of boiling point method is (A) 58.5 g (B) 29.25 g (C) 117 g. (D) O? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for Assuming 100% dissociation in solution the molecular mass of sodium chloride has determined by elevation of boiling point method is (A) 58.5 g (B) 29.25 g (C) 117 g. (D) O?.
Solutions for Assuming 100% dissociation in solution the molecular mass of sodium chloride has determined by elevation of boiling point method is (A) 58.5 g (B) 29.25 g (C) 117 g. (D) O? in English & in Hindi are available as part of our courses for UPSC.
Download more important topics, notes, lectures and mock test series for UPSC Exam by signing up for free.
Here you can find the meaning of Assuming 100% dissociation in solution the molecular mass of sodium chloride has determined by elevation of boiling point method is (A) 58.5 g (B) 29.25 g (C) 117 g. (D) O? defined & explained in the simplest way possible. Besides giving the explanation of
Assuming 100% dissociation in solution the molecular mass of sodium chloride has determined by elevation of boiling point method is (A) 58.5 g (B) 29.25 g (C) 117 g. (D) O?, a detailed solution for Assuming 100% dissociation in solution the molecular mass of sodium chloride has determined by elevation of boiling point method is (A) 58.5 g (B) 29.25 g (C) 117 g. (D) O? has been provided alongside types of Assuming 100% dissociation in solution the molecular mass of sodium chloride has determined by elevation of boiling point method is (A) 58.5 g (B) 29.25 g (C) 117 g. (D) O? theory, EduRev gives you an
ample number of questions to practice Assuming 100% dissociation in solution the molecular mass of sodium chloride has determined by elevation of boiling point method is (A) 58.5 g (B) 29.25 g (C) 117 g. (D) O? tests, examples and also practice UPSC tests.
|
|
Explore Courses for UPSC exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup