UPSC Exam > UPSC Questions > A man standing at the incline at 5m per secon...
Start Learning for Free
A man standing at the incline at 5m per second velocity at the height of 6 metre with the angle of inclined plane is 30 degree at the time for second man throws the ball he slips from the incline and reaches down after 3 seconds of the ball catched then what is velocity of the person who slipped?
Most Upvoted Answer
A man standing at the incline at 5m per second velocity at the height ...
Given data:
- Initial velocity of the man on incline: 5 m/s
- Height of the man on incline: 6 meters
- Angle of inclined plane: 30 degrees
- Time taken for second man to slip down after ball is thrown: 3 seconds
Calculating the velocity of the man who slipped:
1. Calculate the horizontal and vertical components of initial velocity:
- Horizontal component = 5 * cos(30) = 5 * 0.866 = 4.33 m/s
- Vertical component = 5 * sin(30) = 5 * 0.5 = 2.5 m/s
2. Calculate the time taken for the man to reach the ground:
- Time taken to fall from 6 meters: t = sqrt(2h/g) = sqrt(2 * 6 / 9.8) = sqrt(1.22) = 1.1 seconds
3. Calculate the final velocity of the man who slipped:
- Vertical velocity when the man reaches the ground = gt = 9.8 * 1.1 = 10.78 m/s
4. Calculate the velocity of the man who slipped:
- The velocity of the man who slipped can be calculated using Pythagoras theorem:
- Velocity = sqrt((4.33)^2 + (10.78)^2) = sqrt(18.79 + 116.19) = sqrt(134.98) = 11.62 m/s
Therefore, the velocity of the man who slipped from the incline is 11.62 m/s.
- Initial velocity of the man on incline: 5 m/s
- Height of the man on incline: 6 meters
- Angle of inclined plane: 30 degrees
- Time taken for second man to slip down after ball is thrown: 3 seconds
Calculating the velocity of the man who slipped:
1. Calculate the horizontal and vertical components of initial velocity:
- Horizontal component = 5 * cos(30) = 5 * 0.866 = 4.33 m/s
- Vertical component = 5 * sin(30) = 5 * 0.5 = 2.5 m/s
2. Calculate the time taken for the man to reach the ground:
- Time taken to fall from 6 meters: t = sqrt(2h/g) = sqrt(2 * 6 / 9.8) = sqrt(1.22) = 1.1 seconds
3. Calculate the final velocity of the man who slipped:
- Vertical velocity when the man reaches the ground = gt = 9.8 * 1.1 = 10.78 m/s
4. Calculate the velocity of the man who slipped:
- The velocity of the man who slipped can be calculated using Pythagoras theorem:
- Velocity = sqrt((4.33)^2 + (10.78)^2) = sqrt(18.79 + 116.19) = sqrt(134.98) = 11.62 m/s
Therefore, the velocity of the man who slipped from the incline is 11.62 m/s.
Attention UPSC Students!
To make sure you are not studying endlessly, EduRev has designed UPSC study material, with Structured Courses, Videos, & Test Series. Plus get personalized analysis, doubt solving and improvement plans to achieve a great score in UPSC.
|
Explore Courses for UPSC exam
|
|
Top Courses for UPSCView all
A man standing at the incline at 5m per second velocity at the height of 6 metre with the angle of inclined plane is 30 degree at the time for second man throws the ball he slips from the incline and reaches down after 3 seconds of the ball catched then what is velocity of the person who slipped?
Question Description
A man standing at the incline at 5m per second velocity at the height of 6 metre with the angle of inclined plane is 30 degree at the time for second man throws the ball he slips from the incline and reaches down after 3 seconds of the ball catched then what is velocity of the person who slipped? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about A man standing at the incline at 5m per second velocity at the height of 6 metre with the angle of inclined plane is 30 degree at the time for second man throws the ball he slips from the incline and reaches down after 3 seconds of the ball catched then what is velocity of the person who slipped? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A man standing at the incline at 5m per second velocity at the height of 6 metre with the angle of inclined plane is 30 degree at the time for second man throws the ball he slips from the incline and reaches down after 3 seconds of the ball catched then what is velocity of the person who slipped?.
A man standing at the incline at 5m per second velocity at the height of 6 metre with the angle of inclined plane is 30 degree at the time for second man throws the ball he slips from the incline and reaches down after 3 seconds of the ball catched then what is velocity of the person who slipped? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about A man standing at the incline at 5m per second velocity at the height of 6 metre with the angle of inclined plane is 30 degree at the time for second man throws the ball he slips from the incline and reaches down after 3 seconds of the ball catched then what is velocity of the person who slipped? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A man standing at the incline at 5m per second velocity at the height of 6 metre with the angle of inclined plane is 30 degree at the time for second man throws the ball he slips from the incline and reaches down after 3 seconds of the ball catched then what is velocity of the person who slipped?.
Solutions for A man standing at the incline at 5m per second velocity at the height of 6 metre with the angle of inclined plane is 30 degree at the time for second man throws the ball he slips from the incline and reaches down after 3 seconds of the ball catched then what is velocity of the person who slipped? in English & in Hindi are available as part of our courses for UPSC.
Download more important topics, notes, lectures and mock test series for UPSC Exam by signing up for free.
Here you can find the meaning of A man standing at the incline at 5m per second velocity at the height of 6 metre with the angle of inclined plane is 30 degree at the time for second man throws the ball he slips from the incline and reaches down after 3 seconds of the ball catched then what is velocity of the person who slipped? defined & explained in the simplest way possible. Besides giving the explanation of
A man standing at the incline at 5m per second velocity at the height of 6 metre with the angle of inclined plane is 30 degree at the time for second man throws the ball he slips from the incline and reaches down after 3 seconds of the ball catched then what is velocity of the person who slipped?, a detailed solution for A man standing at the incline at 5m per second velocity at the height of 6 metre with the angle of inclined plane is 30 degree at the time for second man throws the ball he slips from the incline and reaches down after 3 seconds of the ball catched then what is velocity of the person who slipped? has been provided alongside types of A man standing at the incline at 5m per second velocity at the height of 6 metre with the angle of inclined plane is 30 degree at the time for second man throws the ball he slips from the incline and reaches down after 3 seconds of the ball catched then what is velocity of the person who slipped? theory, EduRev gives you an
ample number of questions to practice A man standing at the incline at 5m per second velocity at the height of 6 metre with the angle of inclined plane is 30 degree at the time for second man throws the ball he slips from the incline and reaches down after 3 seconds of the ball catched then what is velocity of the person who slipped? tests, examples and also practice UPSC tests.
|
|
Explore Courses for UPSC exam
|
|
Suggested Free Tests
Signup for Free!
Signup to see your scores go up within 7 days! Learn & Practice with 1000+ FREE Notes, Videos & Tests.
|
© EduRev
|
Education Revolution
|
Follow Us
|
Signup to see your scores
go up within 7 days!
Access 1000+ FREE Docs, Videos and Tests
Takes less than 10 seconds to signup