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A man standing at the incline at 5m per second velocity at the height of 6 metre with the angle of inclined plane is 30 degree at the time for second man throws the ball he slips from the incline and reaches down after 3 seconds of the ball catched then what is velocity of the person who slipped?
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A man standing at the incline at 5m per second velocity at the height ...
Given data:
- Initial velocity of the man on incline: 5 m/s
- Height of the man on incline: 6 meters
- Angle of inclined plane: 30 degrees
- Time taken for second man to slip down after ball is thrown: 3 seconds
Calculating the velocity of the man who slipped:
1. Calculate the horizontal and vertical components of initial velocity:
- Horizontal component = 5 * cos(30) = 5 * 0.866 = 4.33 m/s
- Vertical component = 5 * sin(30) = 5 * 0.5 = 2.5 m/s
2. Calculate the time taken for the man to reach the ground:
- Time taken to fall from 6 meters: t = sqrt(2h/g) = sqrt(2 * 6 / 9.8) = sqrt(1.22) = 1.1 seconds
3. Calculate the final velocity of the man who slipped:
- Vertical velocity when the man reaches the ground = gt = 9.8 * 1.1 = 10.78 m/s
4. Calculate the velocity of the man who slipped:
- The velocity of the man who slipped can be calculated using Pythagoras theorem:
- Velocity = sqrt((4.33)^2 + (10.78)^2) = sqrt(18.79 + 116.19) = sqrt(134.98) = 11.62 m/s
Therefore, the velocity of the man who slipped from the incline is 11.62 m/s.
- Initial velocity of the man on incline: 5 m/s
- Height of the man on incline: 6 meters
- Angle of inclined plane: 30 degrees
- Time taken for second man to slip down after ball is thrown: 3 seconds
Calculating the velocity of the man who slipped:
1. Calculate the horizontal and vertical components of initial velocity:
- Horizontal component = 5 * cos(30) = 5 * 0.866 = 4.33 m/s
- Vertical component = 5 * sin(30) = 5 * 0.5 = 2.5 m/s
2. Calculate the time taken for the man to reach the ground:
- Time taken to fall from 6 meters: t = sqrt(2h/g) = sqrt(2 * 6 / 9.8) = sqrt(1.22) = 1.1 seconds
3. Calculate the final velocity of the man who slipped:
- Vertical velocity when the man reaches the ground = gt = 9.8 * 1.1 = 10.78 m/s
4. Calculate the velocity of the man who slipped:
- The velocity of the man who slipped can be calculated using Pythagoras theorem:
- Velocity = sqrt((4.33)^2 + (10.78)^2) = sqrt(18.79 + 116.19) = sqrt(134.98) = 11.62 m/s
Therefore, the velocity of the man who slipped from the incline is 11.62 m/s.
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A man standing at the incline at 5m per second velocity at the height of 6 metre with the angle of inclined plane is 30 degree at the time for second man throws the ball he slips from the incline and reaches down after 3 seconds of the ball catched then what is velocity of the person who slipped?
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A man standing at the incline at 5m per second velocity at the height of 6 metre with the angle of inclined plane is 30 degree at the time for second man throws the ball he slips from the incline and reaches down after 3 seconds of the ball catched then what is velocity of the person who slipped? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about A man standing at the incline at 5m per second velocity at the height of 6 metre with the angle of inclined plane is 30 degree at the time for second man throws the ball he slips from the incline and reaches down after 3 seconds of the ball catched then what is velocity of the person who slipped? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A man standing at the incline at 5m per second velocity at the height of 6 metre with the angle of inclined plane is 30 degree at the time for second man throws the ball he slips from the incline and reaches down after 3 seconds of the ball catched then what is velocity of the person who slipped?.
A man standing at the incline at 5m per second velocity at the height of 6 metre with the angle of inclined plane is 30 degree at the time for second man throws the ball he slips from the incline and reaches down after 3 seconds of the ball catched then what is velocity of the person who slipped? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about A man standing at the incline at 5m per second velocity at the height of 6 metre with the angle of inclined plane is 30 degree at the time for second man throws the ball he slips from the incline and reaches down after 3 seconds of the ball catched then what is velocity of the person who slipped? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A man standing at the incline at 5m per second velocity at the height of 6 metre with the angle of inclined plane is 30 degree at the time for second man throws the ball he slips from the incline and reaches down after 3 seconds of the ball catched then what is velocity of the person who slipped?.
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