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A man fell from a building at the height of 30 m to a range of 4 m then he runs at velocity 4 m per second the overall time taken to reach from top of a building to a distance of 60 m is 4 second then what is the initial velocity?
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A man fell from a building at the height of 30 m to a range of 4 m the...
Analysis of the Problem:
The problem involves a man falling from a height of 30m, coming to a stop at 4m, and then running at a velocity of 4 m/s. The total time taken for the man to reach a distance of 60m is 4 seconds.
Key Points:
- Initial height of fall = 30m
- Stopping height = 4m
- Velocity of running = 4 m/s
- Total distance covered = 60m
- Total time taken = 4 seconds
Calculations:
1. Time taken to fall from 30m to 4m:
Using the equation of motion, we can calculate the time taken to fall from 30m to 4m:
h = ut + (1/2)gt^2
26 = 0 + (1/2)(9.8)t^2
t = √(2*26/9.8) = √(52/9.8) = √5.31 ≈ 2.3 seconds
2. Time taken to run from 4m to 60m:
Total time taken = 4 seconds
Time taken to fall = 2.3 seconds
Time taken to run = 4 - 2.3 = 1.7 seconds
3. Calculate the initial velocity:
Using the equation of motion for running distance:
s = ut
60 - 4 = 4 * u * 1.7
56 = 6.8u
u = 56 / 6.8 ≈ 8.24 m/s
Therefore, the initial velocity of the man was approximately 8.24 m/s.
The problem involves a man falling from a height of 30m, coming to a stop at 4m, and then running at a velocity of 4 m/s. The total time taken for the man to reach a distance of 60m is 4 seconds.
Key Points:
- Initial height of fall = 30m
- Stopping height = 4m
- Velocity of running = 4 m/s
- Total distance covered = 60m
- Total time taken = 4 seconds
Calculations:
1. Time taken to fall from 30m to 4m:
Using the equation of motion, we can calculate the time taken to fall from 30m to 4m:
h = ut + (1/2)gt^2
26 = 0 + (1/2)(9.8)t^2
t = √(2*26/9.8) = √(52/9.8) = √5.31 ≈ 2.3 seconds
2. Time taken to run from 4m to 60m:
Total time taken = 4 seconds
Time taken to fall = 2.3 seconds
Time taken to run = 4 - 2.3 = 1.7 seconds
3. Calculate the initial velocity:
Using the equation of motion for running distance:
s = ut
60 - 4 = 4 * u * 1.7
56 = 6.8u
u = 56 / 6.8 ≈ 8.24 m/s
Therefore, the initial velocity of the man was approximately 8.24 m/s.
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A man fell from a building at the height of 30 m to a range of 4 m then he runs at velocity 4 m per second the overall time taken to reach from top of a building to a distance of 60 m is 4 second then what is the initial velocity?
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A man fell from a building at the height of 30 m to a range of 4 m then he runs at velocity 4 m per second the overall time taken to reach from top of a building to a distance of 60 m is 4 second then what is the initial velocity? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about A man fell from a building at the height of 30 m to a range of 4 m then he runs at velocity 4 m per second the overall time taken to reach from top of a building to a distance of 60 m is 4 second then what is the initial velocity? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A man fell from a building at the height of 30 m to a range of 4 m then he runs at velocity 4 m per second the overall time taken to reach from top of a building to a distance of 60 m is 4 second then what is the initial velocity?.
A man fell from a building at the height of 30 m to a range of 4 m then he runs at velocity 4 m per second the overall time taken to reach from top of a building to a distance of 60 m is 4 second then what is the initial velocity? for UPSC 2024 is part of UPSC preparation. The Question and answers have been prepared according to the UPSC exam syllabus. Information about A man fell from a building at the height of 30 m to a range of 4 m then he runs at velocity 4 m per second the overall time taken to reach from top of a building to a distance of 60 m is 4 second then what is the initial velocity? covers all topics & solutions for UPSC 2024 Exam. Find important definitions, questions, meanings, examples, exercises and tests below for A man fell from a building at the height of 30 m to a range of 4 m then he runs at velocity 4 m per second the overall time taken to reach from top of a building to a distance of 60 m is 4 second then what is the initial velocity?.
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